
#1
Apr605, 06:09 PM

P: 483

If a switch of a circuit system of a wire loop is open, then no current flows. There would also be no magnetic flux and induced current if it remains open, right?
What is the difference between current and induced current? I know the latter arises from a change in the magnetic field, but what else is there to know? Thanks. 



#2
Apr605, 06:24 PM

P: 4,008

marlon 



#3
Apr605, 06:26 PM

P: 4,008

Besides, if there is no current in the primary chain (coming from a battery) there will still be an induced current in the secondary chain (no battery connected to it) because the magnetic field will 'break down' and thus it will induce a current in the second chain. the two chains are mostly interconnected by some ferromagnetic material
marlon 



#4
Apr605, 06:28 PM

Sci Advisor
HW Helper
P: 11,863

Induced EMF
The difference of both names & concepts stands in the cause that produces the curerents."The latter" appears from a change in the magnetic flux (which is a scalar,BTW,so we worry only with changes in time,and not in space)...I believe that's what the theorem/law of Faraday says...
So to use equations,the difference could be visualized from [tex] \vec{E}=\nabla\phi [/tex] and [tex] \mbox{induced \ electromotive \ tension} =\frac{d}{dt}\iint_{S} \vec{B}\cdot \vec{n} \ dS [/tex] Daniel. 



#5
Apr605, 06:33 PM

P: 4,008

Perhaps the most striking difference is the fact that electric potential has meaning only for Efields that are produced by static charges (like the Efield between two electrodes); it has NO meaning for Efields that are produced by induction...
to dextercioby : talking about blablatension and multidimensional integrals ain't gonna do much good in the grade K12level, amigo marlon 



#6
Apr605, 07:07 PM

Sci Advisor
HW Helper
P: 11,863

2.In HS,everyone knows what an electromotive tension is... Daniel. 


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