# Maximum working shear stress and working force?

by BlueCB
Tags: shear force stress
 P: 22 1. The problem statement, all variables and given/known data The maximum shear force of a set of bolts is 1000 kN. The ultimate shear stress is 750 MPa and the safety factor is 3. The diameter of each bolt is 20 mm. a) What is the maximum working shear stress in each bolt? b) The cross sectional area of each bolt? c) The maximum working force of each bolt? 3. The attempt at a solution Radius = half of diameter = 10 mm = 1 cm = 0.01 m Cross sectional area = pi*r^2 = 3.14*1^2 = 3.14 cm^2 = 0.0314 m^2 a) 1000 kN / 0.0314 = 31847133.76 Pa? b) 3.14*1^2 = 3.14 cm^2 = 0.0314 m^2? c) Force = Stress*Area = 31847133.76*0.0314 = 1000000 N = 1000 kN? Is the above correct or do completely different formulas apply when it comes to shear stress and working force?
 HW Helper Thanks P: 5,188 How many square centimeters are in 1 square meter?
 P: 22 10,000...
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P: 8,912

## Maximum working shear stress and working force?

 Quote by BlueCB 10,000...
So correct this:
 3.14 cm^2 = 0.0314 m^2
 P: 22 So 3.14 cm^2 = 0.000314 m^2? So this would change the other answers: a) Working shear stress = Force / Area = 1,000,000 N*0.000314 m^2 = 3184713376 Pa? b) Area = pi*r^2 = pi*1 cm^2 = 3.14 cm^2 = 0.000314 m^2? c) Working force = Stress*Area = 3184713376 Pa*0.000314 m^2 = 1,000,000 N?
 HW Helper Thanks P: 5,188 Reread the problem statement carefully. Why haven't you used this information: "The ultimate shear stress is 750 MPa and the safety factor is 3." Do you understand what this means?
P: 22
 Quote by SteamKing Reread the problem statement carefully. Why haven't you used this information: "The ultimate shear stress is 750 MPa and the safety factor is 3." Do you understand what this means?
If I'm honest, not really; ultimate shear stress, safety factor, maximum working force? The terminology and what their relative units used are, is really confusing me.

Although would I be right in saying that 750 MPa = 750,000,000 N/m^2?

Some clarification would be very much appreciated.
 HW Helper Thanks P: 5,188 Ultimate stress is the maximum stress which can be sustained before failure. A safety factor is applied to the ultimate stress to produce the maximum allowable safe working stress, item a) above. The safety factor accounts for dynamic loading, stress concentrations, and any other unknown factors in calculating stress. Knowing the maximum safe working stress and the size of the bolts, you should be able to calculate c) above. In order to work the problem, you must understand the units as well. The pascal is the SI unit of pressure or stress and 1 Pa = 1 N/m^2.
 P: 22 Is there a formula for shear stress that involves the ultimate shear stress and safety factor?
 HW Helper Thanks P: 5,188 Take this is steps. 1. Knowing the ult. shear stress and the safety factor, what is the max. allowable working stress?
P: 22
 Quote by SteamKing Take this is steps. 1. Knowing the ult. shear stress and the safety factor, what is the max. allowable working stress?
750 MPa = 750,000,000 Pa / 3 = 250,000,000 Pa = 250 MPa (max working stress)?
or
750,000,000 Pa*3 = 2,250,000,000 Pa = 2.25 GPa (max working stress)?
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 Quote by BlueCB 750 MPa = 750,000,000 Pa / 3 = 250,000,000 Pa = 250 MPa (max working stress)? or 750,000,000 Pa*3 = 2,250,000,000 Pa = 2.25 GPa (max working stress)?
It's a safety factor. To be safe, do you think the working stress to which it should be subjected would be more or less than its calculated ultimate stress?
P: 22
 Quote by haruspex It's a safety factor. To be safe, do you think the working stress to which it should be subjected would be more or less than its calculated ultimate stress?
Less, would make more sense (if its to be safe).

So in that case, does 250 MPa sound about right for the max working shear stress?

And then: max working shear stress*cross sectional area = max working force
= 250,000,000 Pa*0.000314 m^2 = 78500 N = 78.5 kN?
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