Register to reply 
Maximum working shear stress and working force?by BlueCB
Tags: shear force stress 
Share this thread: 
#1
Jul2713, 05:34 PM

P: 22

1. The problem statement, all variables and given/known data
The maximum shear force of a set of bolts is 1000 kN. The ultimate shear stress is 750 MPa and the safety factor is 3. The diameter of each bolt is 20 mm. a) What is the maximum working shear stress in each bolt? b) The cross sectional area of each bolt? c) The maximum working force of each bolt? 3. The attempt at a solution Radius = half of diameter = 10 mm = 1 cm = 0.01 m Cross sectional area = pi*r^2 = 3.14*1^2 = 3.14 cm^2 = 0.0314 m^2 a) 1000 kN / 0.0314 = 31847133.76 Pa? b) 3.14*1^2 = 3.14 cm^2 = 0.0314 m^2? c) Force = Stress*Area = 31847133.76*0.0314 = 1000000 N = 1000 kN? Is the above correct or do completely different formulas apply when it comes to shear stress and working force? 


#2
Jul2713, 06:06 PM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 6,334

How many square centimeters are in 1 square meter?



#3
Jul2713, 09:58 PM

P: 22

10,000...



#4
Jul2813, 02:02 AM

Homework
Sci Advisor
HW Helper
Thanks
P: 9,656

Maximum working shear stress and working force?



#5
Jul2813, 06:24 AM

P: 22

So 3.14 cm^2 = 0.000314 m^2?
So this would change the other answers: a) Working shear stress = Force / Area = 1,000,000 N*0.000314 m^2 = 3184713376 Pa? b) Area = pi*r^2 = pi*1 cm^2 = 3.14 cm^2 = 0.000314 m^2? c) Working force = Stress*Area = 3184713376 Pa*0.000314 m^2 = 1,000,000 N? 


#6
Jul2813, 07:32 AM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 6,334

Reread the problem statement carefully. Why haven't you used this information:
"The ultimate shear stress is 750 MPa and the safety factor is 3." Do you understand what this means? 


#7
Jul2813, 07:58 AM

P: 22

Although would I be right in saying that 750 MPa = 750,000,000 N/m^2? Some clarification would be very much appreciated. 


#8
Jul2813, 11:40 AM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 6,334

Ultimate stress is the maximum stress which can be sustained before failure. A safety factor is applied to the ultimate stress to produce the maximum allowable safe working stress, item a) above. The safety factor accounts for dynamic loading, stress concentrations, and any other unknown factors in calculating stress. Knowing the maximum safe working stress and the size of the bolts, you should be able to calculate c) above.
In order to work the problem, you must understand the units as well. The pascal is the SI unit of pressure or stress and 1 Pa = 1 N/m^2. 


#9
Jul2813, 01:47 PM

P: 22

Is there a formula for shear stress that involves the ultimate shear stress and safety factor?



#10
Jul2813, 03:20 PM

Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 6,334

Take this is steps.
1. Knowing the ult. shear stress and the safety factor, what is the max. allowable working stress? 


#11
Jul2813, 03:26 PM

P: 22

or 750,000,000 Pa*3 = 2,250,000,000 Pa = 2.25 GPa (max working stress)? 


#12
Jul2813, 06:24 PM

Homework
Sci Advisor
HW Helper
Thanks
P: 9,656




#13
Jul2913, 12:02 PM

P: 22

So in that case, does 250 MPa sound about right for the max working shear stress? And then: max working shear stress*cross sectional area = max working force = 250,000,000 Pa*0.000314 m^2 = 78500 N = 78.5 kN? 


#14
Jul2913, 04:27 PM

Homework
Sci Advisor
HW Helper
Thanks
P: 9,656




Register to reply 
Related Discussions  
Working out maximum stress and Factor of safety  Engineering, Comp Sci, & Technology Homework  18  
Working out shear force  Engineering, Comp Sci, & Technology Homework  11  
Drawing a shear force diagram with loads working at an angle  Introductory Physics Homework  1  
Principal Stresses, Calculating Stress in the x and y direction and working out shear  Engineering, Comp Sci, & Technology Homework  0  
Why can maximum shear stress in a web be replaced by the average shear stress?  Engineering, Comp Sci, & Technology Homework  4 