Calculate Energy Req'd for 2 kmol HF from 2.0kg H and 38 kg F

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SUMMARY

The discussion centers on calculating the energy produced from the reaction of hydrogen (H) and fluorine (F) to form hydrogen fluoride (HF). The reaction yields approximately 500 kJ/mol of energy. For 2.0 kg of H and 38 kg of F, the total energy produced when generating 2 kmol of HF is confirmed to be 5.0 x 105 kJ. This calculation is based on stoichiometric principles and the known energy release per mole of reaction.

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anias
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I Have A Question about FUSION! Please Help!

the reaction of H and F produces about 500 kj/mol of energy:

how much energy is produced by the reaction of 2.0kg of H with 38 kg of F to produce 2 kmol of HF?

i know the answer is 5.0x 10 to the exponent 5 kJ... but I'm not sure why...


PLEASE HELP!
thanks for your time =D
 
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