- #1
MathJakob
- 161
- 5
I know how the very basics but then I get given a question like this.
##\sqrt{9-3x}## and I think I can divide both by 3. ##3\sqrt{3-x}## and so ##x=3##
Then I get ##\sqrt{4x+12}## and again I can take 4 from each ##4\sqrt{x+3}## and so ##x=-3##
Is this the correct way to be solving these? Because I'm looking down the page and it starts getting real complicated looking, real fast and was just wondering if there is a simple way to go about solving these?
Simplify: ##{\sqrt\frac{9a}{8b^2}}## is the next question I face
##\sqrt{9-3x}## and I think I can divide both by 3. ##3\sqrt{3-x}## and so ##x=3##
Then I get ##\sqrt{4x+12}## and again I can take 4 from each ##4\sqrt{x+3}## and so ##x=-3##
Is this the correct way to be solving these? Because I'm looking down the page and it starts getting real complicated looking, real fast and was just wondering if there is a simple way to go about solving these?
Simplify: ##{\sqrt\frac{9a}{8b^2}}## is the next question I face
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