Calculating Boiler Efficiency for Year-Round Use

Click For Summary
SUMMARY

The discussion focuses on calculating the overall efficiency of a boiler across different operational periods, specifically addressing two distinct efficiencies, A and B, for time periods T1 and T2. The method for calculating the overall efficiency involves either a simple average formula, (A*T1 + B*T2)/(T1+T2), or integrating the efficiencies over time for a more precise result. Additionally, the conversation highlights the importance of distinguishing between efficiency and availability, emphasizing that availability refers to the operational capacity of the boiler rather than its efficiency during use.

PREREQUISITES
  • Understanding of thermodynamic efficiency concepts
  • Familiarity with time-weighted averages
  • Knowledge of boiler operation and efficiency metrics
  • Basic principles of availability and capacity factors
NEXT STEPS
  • Research methods for integrating time-dependent efficiencies
  • Learn about boiler efficiency metrics and standards
  • Explore the concept of availability in power generation
  • Study the impact of operational conditions on boiler performance
USEFUL FOR

Engineers, energy analysts, and facility managers involved in boiler operation and efficiency optimization will benefit from this discussion.

TSN79
Messages
422
Reaction score
0
I have a boiler which for a certain period of the year has a spesific boiler efficiency, let's call it A. For another period of the year the boiler isn't used that much, and so it now has a different boiler efficiency B for this period. How do I find the overall efficiency for the whole year?

Hope someone can help me... :confused:
 
Engineering news on Phys.org
Thermodynamic efficiency is pretty much independent of time, unless it degrades due to changes in the system which are time dependent, e.g. build up of deposits.

If one has two time periods T1 and T2, and two rates A and B during those periods, then a simple average is (A*T1 + B*T2)/(T1+T2), otherwise one has to integrate A(t), B(t) over the corresponding times and use the appropriate averaging technique.

Now as for efficiency, are you sure the problem is not calling for 'availability'. Some plants can be operable, but are not needed, and therefore will have a low capacity factor.

Availablity is the time that a plant can operate, and capacity is based on the actual time of operation.

A plant down for repairs has no availability.
 
Astronuc said:
If one has two time periods T1 and T2, and two rates A and B during those periods, then a simple average is (A*T1 + B*T2)/(T1+T2), otherwise one has to integrate A(t), B(t) over the corresponding times and use the appropriate averaging technique.
I think he is talking about part load and standby type efficiencies. Using the correct values for these efficiencies and using Astronu's average calculation should give a pretty good overall efficiency estimation.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
Replies
13
Views
6K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
14K
  • · Replies 15 ·
Replies
15
Views
5K