What are the Values of X and Y in the Equation X^2 - Y^2 = X - Y?

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Discussion Overview

The discussion revolves around finding the values of x and y in the equation x² - y² = x - y, with the condition that x does not equal y. Participants explore potential solutions and methods for solving the equation.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant suggests that the only solution occurs when x and y are both equal to one, leading to the equation being satisfied as 0 = 0.
  • Another participant points out that the original question specifies x not equal to y, and proposes that the equation can be factored to yield x + y = 1, indicating possible solutions of (0, 1) or (1, 0) for positive integers.
  • A participant questions the relevance of implicit differentiation to the problem, seeking clarification on its applicability.
  • There is a general uncertainty about how the problem relates to calculus, with multiple participants expressing confusion regarding this connection.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the solutions, as some focus on the case where x equals y while others emphasize the requirement that x does not equal y. The discussion remains unresolved regarding the broader implications of the equation and its relation to calculus.

Contextual Notes

There are limitations in the discussion regarding assumptions about the types of numbers (e.g., integers, positive integers) being considered, as well as the lack of clarity on the relevance of calculus to the problem.

khalid_kacst
x^2 - y^2 = x - y , ?

if y not equal x .

what is y and x when

x^2 - y^2 = x - y

---------------------------
 
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Only solution I can think of is when x and y is equal to one.
You get:

x = 1; y = 1;

(1)^2 - (1)^2 = (1) - (1)
==> 0 = 0
 
Originally posted by renedox
Only solution I can think of is when x and y is equal to one.
You get:

x = 1; y = 1;

(1)^2 - (1)^2 = (1) - (1)
==> 0 = 0
he asked for solution in which x doesn't equal y.

now i know it's simple but the question seems to be simple
x^2-y^2=x-y
(x-y)*(x+y)=x-y /x-y
x+y=1
now for positive integers it could only be x=0 y=1 or the opposite, the other solutions are negative integers and positive ones.

btw, can someone explain how is this a question about calculus?
 
Unless there is a further restriction on x and y (the original question didn't include any), then x+y=1, for any x, will do.
 
Originally posted by loop quantum gravity
he asked for solution in which x doesn't equal y.

Gah, don't be tired and browes PF at the same time :P
 
use implicit differentiation and find the derivative
 
use implicit differentiation and find the derivative
What has this got to do with it??
 
I also wonder the same , and how is that will be useful ?
 

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