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Gauss Law |
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| Apr10-05, 09:18 AM | #1 |
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Gauss Law
I used the formula (E * Area * cos(theta)) and got the wrong answer (.02529) and I really don't understand why. I need help
The square surface shown measures 4.0 mm on each side. It is immersed in a uniform electric field with magnitude E = 1930 N/C. The field lines make an angle of 35° with a normal to the surface, as shown. Take the normal to be "outward," as though the surface were one face of a box. Calculate the electric flux through the surface. |
| Apr10-05, 09:24 AM | #2 |
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It looks correct (probably not the final #).U may have to check the units ([itex] \left(1\mbox{mm})\right)^{2}=10^{-6} \mbox{m}^{2} [/itex]...
Daniel. |
| Apr10-05, 11:38 AM | #3 |
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35 degrees to the normal is 55 degrees to the surface. Did you try that?
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| Apr10-05, 11:41 AM | #4 |
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Gauss Law
Halls,she needs the scalar product between the electric field vector and the normal to the surface,which make an angle of 35° between them...
Daniel. |
| Apr10-05, 12:58 PM | #5 |
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I tried 55, and it didn't work.
Is electrical flux supposed to be negative? Thats all I can think of. I don't know if that's right. |
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