Troubleshooting Electric Flux Calculation on a Square Surface

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Homework Help Overview

The discussion revolves around calculating electric flux through a square surface immersed in a uniform electric field. The original poster attempts to apply the formula for electric flux but encounters difficulties with the result and understanding the implications of angles involved.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the electric flux formula, questioning the angle used in calculations and the importance of unit conversion. There are considerations about the direction of the electric field and its impact on the sign of the flux.

Discussion Status

The discussion is ongoing, with participants providing insights on potential issues with the original poster's calculations and assumptions. There is no explicit consensus, but various angles and interpretations are being explored.

Contextual Notes

Participants note the lack of a visual representation of the problem, which may contribute to ambiguity in understanding the electric field's direction relative to the surface.

Rave Grrl
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I used the formula (E * Area * cos(theta)) and got the wrong answer (.02529) and I really don't understand why. I need help

The square surface shown measures 4.0 mm on each side. It is immersed in a uniform electric field with magnitude E = 1930 N/C. The field lines make an angle of 35° with a normal to the surface, as shown. Take the normal to be "outward," as though the surface were one face of a box. Calculate the electric flux through the surface.
 
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It looks correct (probably not the final #).U may have to check the units ([itex]\left(1\mbox{mm})\right)^{2}=10^{-6} \mbox{m}^{2}[/itex]...

Daniel.
 
35 degrees to the normal is 55 degrees to the surface. Did you try that?
 
Halls,she needs the scalar product between the electric field vector and the normal to the surface,which make an angle of 35° between them...

Daniel.
 
I tried 55, and it didn't work.

Is electrical flux supposed to be negative? Thats all I can think of. I don't know if that's right.
 
Depends on the sense of the electric field.If it enters the page or not.Your problem is pretty vague in this issue,because you haven't provided the drawing/picture.

Daniel.
 

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