What is the Heat of Combustion for Quinone in kJ/mol?

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SUMMARY

The heat of combustion for quinone (C6H4O2) can be calculated using the formula Q = C × ΔT, where Q is the heat absorbed, C is the heat capacity of the calorimeter, and ΔT is the change in temperature. In this case, with a heat capacity of 1.56 kJ/C and a temperature increase of 3.2 C, the total heat absorbed is 4.992 kJ. To find the heat of combustion per mole, divide this value by the number of moles of quinone in the 0.196 g sample, which is approximately 0.0011 moles, resulting in a heat of combustion of approximately 4,500 kJ/mol.

PREREQUISITES
  • Understanding of calorimetry principles
  • Knowledge of mole calculations
  • Familiarity with the concept of heat capacity
  • Basic chemistry knowledge regarding combustion reactions
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  • Learn about bomb calorimetry techniques
  • Study the calculation of heat of combustion for various organic compounds
  • Explore the relationship between heat capacity and temperature change
  • Investigate the properties and applications of quinone in chemical reactions
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A 0.196 g sample of quinone (C6H4O2) is burned in a bomb calorimeter that has a heat capacity of 1.56 kJ/C. What is the heat of combustion (kJ/mol) if the temperature increases by 3.2 C?

-I have no idea how to do this problem...
 
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Look at your text. It has examples of similar problems.
 

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