Calculating Power for Pumping Water to a Tower

[Nx2]

Hi guys, I was doing some homework when I got stuck on this question I came upon. It goes as follows...

Water is being pumped up to a water tower, which is 92.0m high. The flow rate up to the top the tower is 75L/s and each litre of water has a mass of 1.00kg. what power is required to keep up this flow rate to the tower?

Ok, so I know the formula for power is P = W/t, so I changed W into F•d and now my equation is P = (F•d)/t. then I changed F into mg and got the equation P = (mg•d)/t.
Ok, now I am not sure if what I am doing is right but I don’t know where to go from here… they gave me velocity but I don’t know what to do with it. Like I subbed all my values in like the mass, gravity and distance but I don’t know what to do with the “75L/s and each litre is 1.00kg.”…. any help would be appreciated, thanks.

- Tu

 

[Gokul43201]

You have :
$$P = \frac {mgh}{t} = gh \cdot \frac {m}{t}$$

Does that help ?

 

[Nx2]

ok... so... hmmm lol sorry i don't understand where that equation was derived from... h is height right?

 

[Gokul43201]

Yes, h is the height. I just wrote what you had written and re-arranged the terms to bring out the factor (m/t). m/t is mass per unit time. Do you not know the value of this ?

 

[Nx2]

sorry... yea... we never learned that b4.

 

[Gokul43201]

sorry... yea... we never learned that b4.

I'm not sure what you mean by this. Do you now understand how to solve the problem, or don't you ?

 

[Nx2]

ooo... ok i tried it and i got the answer!... thnx a lot i appreciate it. good help.

- Tu

 

[Nx2]

yea i understand... thnx