Register to reply 
Squaring of vectors in absolute value 
Share this thread: 
#1
Sep2613, 02:09 PM

P: 378

Is [itex]\vec{a}[/itex]+[itex]\vec{b}[/itex][itex]^{2}[/itex] equal to the same thing as ([itex]\vec{a}[/itex]+[itex]\vec{b}[/itex])[itex]^{2}[/itex]? And when is it equal to √(a[itex]^{2}[/itex]+b[itex]^{2}[/itex])?
Thanks. 


#2
Sep2613, 02:45 PM

Mentor
P: 21,215

[itex](\vec{a} +\vec{b})^2 [/itex] Or instead of the itex tags, you can use ## delimiters at the front and back. 


#3
Sep2713, 12:40 AM

P: 378

Thank you for the reply and the tip. But about the √(a^2+b^2)?? My second part of the question?



#4
Sep2713, 01:41 AM

P: 32

Squaring of vectors in absolute value



#5
Sep2713, 02:08 AM

P: 1,290




#6
Sep2713, 02:09 AM

P: 378

Okay. Thank you, yes, it is exactly what I meant.



Register to reply 
Related Discussions  
The Replacement of Squaring the Individual Distances with Absolute Values in Variance  Set Theory, Logic, Probability, Statistics  1  
Squaring a sum  Calculus & Beyond Homework  6  
Translational Kinetic energy, am i squaring vectors correctly?  Introductory Physics Homework  2  
How do you square cosB?  Introductory Physics Homework  4  
Squaring a bra  Advanced Physics Homework  8 