Radiation loss

TSN79

I analyzed the chimney gas from a 70 kWboiler burning pellets. I found the temperature to be 140C, the CO2 value was 8%, and the room temp was 22C. Is it possible from this to calculate the boilers radiation loss? If not, what other information do I need? I used Siegert's formula to find the chimney loss by [tex]0,8\frac{140-22}{8}=11,8[/tex] where 0,8 is a constant used for pellets.

Gokul43201

You can actually calculate an upper bound on the heat radiated by the boiler if you knew the temperature in the boiler. Not all of this radiation will contribute to a loss, and that fraction will depend on the construction (materials and geometry) of the boiler.