Can you help me convert compounds with water molecules?

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Homework Help Overview

The discussion revolves around converting hydrated compounds, specifically manganese nitrate hexahydrate to manganese sulfate tetrahydrate and calcium acetate monohydrate to calcium nitrate tetrahydrate. The focus is on understanding the role of water molecules in these conversions.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants explore the chemical reactions involved in converting the hydrated compounds and question how recrystallization leads to specific hydration states in the products. There is a focus on the stoichiometry of the reactions and the implications of water in the equations.

Discussion Status

Some participants are seeking clarification on the process of conversion and the role of water in the reactions. There is an acknowledgment of the challenges in understanding the stoichiometric relationships, and guidance is being offered regarding the necessity of acids being in solution for the reactions to proceed as described.

Contextual Notes

Participants express confusion specifically about the "water" components in the compounds and the implications of recrystallization on the final products. There is an indication that the discussion is constrained by the need for specific ionic equations and the understanding of stoichiometric principles.

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I'm having a lot of trouble with some of these questions. Please help

Converting manganse nitrate-6-water to manganese sulfate-4-water

Converting calcium acetate-1-water to calcium nitrate-4-water.

It's the "water" bits that confuse me. I just need a couple of ionic equations to show the conversion (like dissolving it in water, etc).

Thank you.
 
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Converting,like reacting with certain compounds?

For example

[tex]Mn\left(NO_{3}\right)_{2}\cdot 6H_{2}O+H_{2}SO_{4}\rightarrow MnSO_{4}+2HNO_{3}+6H_{2}O[/tex]

How do you know that by recrystalization of the reaction products u'd get [itex]MnSO_{4}\cdot 4H_{2}O[/itex]...?


Daniel.
 
As for the second

[tex]Ca(CH_{3}-COO)_{2}\cdot H_{2}O+2HNO_{3}\rightarrow Ca\left(NO_{3}\right)_{2}+2CH_{3}-COOH[/tex]

Again,by recrystalization,how do u know it's going to be a [itex]Ca\left(NO_{3}\right)_{2}\cdot 4H_{2}O[/itex] ?



Daniel.
 
That's exactly what I'm having trouble with. Thanks for your help. :smile:
 
Well,those acids must be in solution,u can see that,doing the second one stoichiometrically,u won't get that 4 molecules of water.


Daniel.
 

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