Solving Math Problems: Step-by-Step Guide

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Homework Help Overview

The discussion revolves around understanding trigonometric concepts, specifically the sine, cosine, and tangent functions, as well as their applications in solving problems from a worksheet. Participants are seeking clarification on these concepts and their usage in problem-solving.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express a desire for step-by-step guidance on solving problems, with some questioning the application of SOHCAHTOA. Others inquire about the sine and cosine rules, indicating a need for foundational understanding.

Discussion Status

Some participants have provided definitions of trigonometric functions and have attempted to clarify their usage. There is an ongoing exploration of the sine and cosine rules, with no explicit consensus reached on the best approach to the problems presented.

Contextual Notes

One participant mentions being in special education and feeling challenged by the material, which may influence the discussion dynamics and the level of detail required in explanations.

wundumbbutt
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can someone help me solve at least one problem on the worksheet and show me the steps to get the answer

http://img.photobucket.com/albums/v128/babycinnam0r0ll/scan.jpg
 
Last edited by a moderator:
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wundumbbutt said:
can someone help me solve at least one problem on the worksheet and show me the steps to get the answer

http://img.photobucket.com/albums/v128/babycinnam0r0ll/scan.jpg
Do you know SOHCAHTOA?
 
Last edited by a moderator:
christinono said:
Do you know SOHCAHTOA?
um...kinda how do u know which one you use? sorry I am in special ed I am super slow in understanding even the simple stuff
 
[tex]sin\theta = \frac{opposite}{adjacent}[/tex]
[tex]cos\theta = \frac{adjacent}{hypotenuse}[/tex]
[tex]tan\theta = \frac{opposite}{adjacent}[/tex]

Use the one which contains the unknown variable and the variable you are given.
 
[tex]sin\theta = \frac{opposite}{adjacent}[/tex]

Actually, it's:

[tex]sin\theta = \frac{opposite}{hypotenuse}[/tex] :wink:

OP, do you know the sine and cosine rules?
 
Berislav said:
Actually, it's:

[tex]sin\theta = \frac{opposite}{hypotenuse}[/tex] :wink:

OP, do you know the sine and cosine rules?

what are the sine and cosine rules?
 

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