How does light reflection occur after being absorbed by atoms?

In summary, when light is absorbed by an atom, it is emitted again in an arbitrary direction and the momentum is conserved by the recoil of the atom or solid surface. The direction of reflection is determined by the conduction band dispersion in metals, while in other materials it is determined by the reciprocal lattice and the first Brillouin zone. In terms of quantum mechanics, a single photon has a probability of reflecting in various directions, but when many photons are present, they appear to follow a classical model. Reflection involves the photon driving electrons and the electrons retransmitting the photon.
  • #1
jet10
36
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As far as I know, when light is absorbed by an atom, it is emitted again in an arbitrary direction.
1) what happens to the momentum?
2) why does light always reflect in a certain direction, depending on its incident direction, if reflection is an effect of emission after absorption?

Thanks
 
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  • #2
jet10 said:
As far as I know, when light is absorbed by an atom, it is emitted again in an arbitrary direction.
1) what happens to the momentum?

Notice that there is a HUGE atom in the vacinity. This beast is the one doing the recoil, so you hardly notice it.

2) why does light always reflect in a certain direction, depending on its incident direction, if reflection is an effect of emission after absorption?

Thanks

Now this is a slightly different situation than above, because you will notice that reflection occurs not from an atom (or even a gas), but rather from solid surfaces like metals. This should tell you that there is a different mechanism for reflection here. The most common and dominant process is due to the presence of conduction electrons in metals (it is why metals make very good mirrors). To know why light reflect at a certain direction would require knowledge of the conduction band dispersion. However, it is sufficient to note that the PARALLEL momentum of the original light is conserved (technical explanation: conduction electron can make a k --> k+G transition, where G is the reciprocal lattice vector for a Bloch crystal), while the rest of the solid recoils and retransmit, in the opposite direction, the perpendicular momentum. Thus, when you have the same parallel momentum, but an equal but opposite perpendicular momentum, you get the familar reflection law.

Note that there is a 180 degree phase change of the reflected light, because the conduction electrons react in the "opposite manner" to the incoming light, and thus they reradiate light with an opposite phase. If we have positrons making up the conduction band, we won't have such a phase change.

Zz.
 
  • #3
Though I learned it recently, I am still not very familiar with the term reciprocal lattice. As far as I understand. This relation k-k'=G has to hold in order to observe a maximum intensity. How does this affect the conservation of parallel momentum or the recoiling of the perpendicular?

Electrons in metal can jump into the conduction band very easily. This makes it easy for them to absorb and reemit. But how does this help us with the direction of reflection? I haven't heard about conduction band dispersion before. I think I should read about it. But would be glad if you could explain to me a little.

How is it that only the perpendicular momentum recoils but not the parallel? It reminds me of tennis. The ball hits the ground and bouces back, but it keeps going the same horizontal direction. What happens there microscopically?
 
  • #4
jet10 said:
Though I learned it recently, I am still not very familiar with the term reciprocal lattice. As far as I understand. This relation k-k'=G has to hold in order to observe a maximum intensity. How does this affect the conservation of parallel momentum or the recoiling of the perpendicular?

Electrons in metal can jump into the conduction band very easily. This makes it easy for them to absorb and reemit. But how does this help us with the direction of reflection? I haven't heard about conduction band dispersion before. I think I should read about it. But would be glad if you could explain to me a little.

How is it that only the perpendicular momentum recoils but not the parallel? It reminds me of tennis. The ball hits the ground and bouces back, but it keeps going the same horizontal direction. What happens there microscopically?

I have no clue on how to explain this to you without invoking the recriprocal lattice, the first Brillouin zone, and extended Brillouin zone scheme, etc. Since you haven't gotten to this yet, I think all my explanation will just simply won't make any sense right now.

Also, note that electrons do NOT need to jump into the conduction band in a metal. They are ALREADY there, even at T=0K. The conduction band in a metal is occupied already. It is in an insulator and semiconductor that the conduction band is empty at T=0K.

Zz.
 
  • #5
Reflection is not the same process as absorption and reemission as I understand it. If the reflecting surface did absorb the photon, the surface would be black, and you would not see any reflection at all.

Reflection is actually a photon driving an electron (or electrons), and the electrons retransmitting the photon (much like an antenna).

I thought this might be where some of the confusion is coming from.

Claude.
 
  • #6
Claude, looking at it from the classical ED point of view, the electric field forces the electrons to vibrate and thus at the same time, the electrons regenerate the photon again. Is this what you mean?
 
  • #7
I have just read a book on this subject: QED: the strange theory of light and matter by RP Feynman. It is quite easy to understand! The fact is that i can't give a conclusion in a few lines...

Greetz :tongue:
 
  • #8
jet10 said:
Claude, looking at it from the classical ED point of view, the electric field forces the electrons to vibrate and thus at the same time, the electrons regenerate the photon again. Is this what you mean?

Yes.

Claude.
 
  • #9
My problem is to think in qm terms. I think I need to go study Solid State Physics first.
 
  • #10
As I understand it from reading, a single photon has a quantum probability of reflecting in a variety of directions around the point of impact. It is only a beam of many photons that appears to obey the classical model.

juju
 
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  • #11
correct me if I am wrong, juju. Do you mean that the atoms reemits the light in an arbitrary direction, but since we are speaking about many many photons, it seems as if it is making a spherical wave, interfering with those waves reemitted by its neighbouring atoms? Only photons in a certain direction interferes constructively. One of these directions is at the reflection angle?
 

1. What is the process of light being absorbed by an atom?

When an atom absorbs light, it means that the energy of the light is transferred to the atom, causing its electrons to become excited and move to higher energy levels.

2. How does the absorption of light affect the atom's properties?

When an atom absorbs light, its properties can change depending on the energy and frequency of the absorbed light. For example, if the absorbed light has enough energy, it can cause the atom to become ionized, losing or gaining electrons.

3. What determines the color of light that is absorbed by an atom?

The color of light that is absorbed by an atom is determined by the energy levels of its electrons. Each atom has a unique set of energy levels, which correspond to specific colors of light that they can absorb.

4. Can an atom absorb all colors of light?

No, atoms can only absorb specific colors of light that correspond to the energy levels of their electrons. For example, a sodium atom can only absorb yellow light, while a hydrogen atom can absorb red, blue, and violet light.

5. What happens to the absorbed light after it interacts with an atom?

After light is absorbed by an atom, it can be re-emitted as a different color of light, reflected, or converted into other forms of energy such as heat. The fate of the absorbed light depends on the properties and interactions of the atom.

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