
#1
Nov2213, 03:11 AM

P: 37

Hi all,
I try to understand the difference which can made by using or not using NWA .. I have a process have cross section (p p > x x) ~ 10^5 pb , where x is a paricle have mass mx = 2 TeV and dominant decay channel (x > b b~) with Gamma (x > b b~) ~ 6 * 10^2 GeV , while sigma ( p p > x x , x > b b~) ~ 10^6 pb (I calculate this with a program not using the NWA).. It's clear that if NWA is used sigma ( p p > x x , x > b b~) will just ~ 10^5 pb since BR (x > b b~) =1, so what does mean 10^5 (NWA) and 10^6 (non NWA) Is that what meant by that NWA has ## \Gamma/m ## approximation ? Regards, Safinaz 



#2
Nov2213, 12:04 PM

P: 81

Let me try to understand more.
Are you pair producing these two new particles? Then looking at the final state of 4 bs? And your partial width of x>b bbar is 5% of the mass of x? 



#3
Nov2213, 02:09 PM

P: 37

Hi,
I think I get it, thanks. S. 


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