
#1
Apr2405, 04:15 AM

P: 14

Hi,
I am really confused with circle theorems, attached is a diagram and I need to find out ABC and CBO. I have worked out that angle ACB is x degrees, and also know that angle OAC is equal to angle OBC. But I don't know how to work out the what either are Thanks Graham 



#2
Apr2405, 04:17 AM

P: 14

Is this something to do with opposite angles on a cyclic quadratic add up to 180?




#3
Apr2405, 04:17 AM

P: 2,223

If youcan post it on the web somewhere, we'd be able to see it before tomorrow. It has to be pre approved.




#4
Apr2405, 04:19 AM

P: 14

Maths  Circle Theorems 



#5
Apr2405, 04:31 AM

P: 2,223

Do you know anything specific about the inscription of the triangle in the circle? I want to say that the arcs between A B and C are 120 degrees, but I can't tell if thats whatits supposed to be. 



#6
Apr2405, 04:36 AM

P: 14

Find in terms of X, expressions for the angles:
 ABC  CBO The points A,B, and C lie on the centre circle O. 



#7
Apr2405, 04:47 AM

P: 2,223

Since AC = BC, the triangle ABC is isosceles, and angles ABC and BAC are equal. The sum of all three angles is 180.
Where y is angle ABC 180 = 2y+x y = 90x/2 Do you have the answer? 


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