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Maths - Circle Theorems

 
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Apr24-05, 04:15 AM   #1
 

Maths - Circle Theorems


Hi,

I am really confused with circle theorems, attached is a diagram and I need to find out ABC and CBO.

I have worked out that angle ACB is x degrees, and also know that angle OAC is equal to angle OBC.

But I don't know how to work out the what either are

Thanks

Graham
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maths.GIF  
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Apr24-05, 04:17 AM   #2
 
Is this something to do with opposite angles on a cyclic quadratic add up to 180?
Apr24-05, 04:17 AM   #3
 
If youcan post it on the web somewhere, we'd be able to see it before tomorrow. It has to be pre approved.
Apr24-05, 04:19 AM   #4
 

Maths - Circle Theorems


See www.kgmm.co.uk/maths.GIF

Many thanks!

Graham
Apr24-05, 04:31 AM   #5
 
I am really confused with circle theorems, attached is a diagram and I need to find out ABC and CBO.
Arc ABC? Angle ABC? You didnt label this angle.


Do you know anything specific about the inscription of the triangle in the circle? I want to say that the arcs between A B and C are 120 degrees, but I can't tell if thats whatits supposed to be.
Apr24-05, 04:36 AM   #6
 
Find in terms of X, expressions for the angles:

- ABC
- CBO

The points A,B, and C lie on the centre circle O.
Apr24-05, 04:47 AM   #7
 
Since AC = BC, the triangle ABC is isosceles, and angles ABC and BAC are equal. The sum of all three angles is 180.
Where y is angle ABC
180 = 2y+x
y = 90-x/2

Do you have the answer?
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