Maths - Circle Theorems


by grahammm
Tags: circle, maths, theorems
grahammm
grahammm is offline
#1
Apr24-05, 04:15 AM
P: 14
Hi,

I am really confused with circle theorems, attached is a diagram and I need to find out ABC and CBO.

I have worked out that angle ACB is x degrees, and also know that angle OAC is equal to angle OBC.

But I don't know how to work out the what either are

Thanks

Graham
Attached Thumbnails
maths.GIF  
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grahammm
grahammm is offline
#2
Apr24-05, 04:17 AM
P: 14
Is this something to do with opposite angles on a cyclic quadratic add up to 180?
whozum
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#3
Apr24-05, 04:17 AM
P: 2,223
If youcan post it on the web somewhere, we'd be able to see it before tomorrow. It has to be pre approved.

grahammm
grahammm is offline
#4
Apr24-05, 04:19 AM
P: 14

Maths - Circle Theorems


See www.kgmm.co.uk/maths.GIF

Many thanks!

Graham
whozum
whozum is offline
#5
Apr24-05, 04:31 AM
P: 2,223
I am really confused with circle theorems, attached is a diagram and I need to find out ABC and CBO.
Arc ABC? Angle ABC? You didnt label this angle.


Do you know anything specific about the inscription of the triangle in the circle? I want to say that the arcs between A B and C are 120 degrees, but I can't tell if thats whatits supposed to be.
grahammm
grahammm is offline
#6
Apr24-05, 04:36 AM
P: 14
Find in terms of X, expressions for the angles:

- ABC
- CBO

The points A,B, and C lie on the centre circle O.
whozum
whozum is offline
#7
Apr24-05, 04:47 AM
P: 2,223
Since AC = BC, the triangle ABC is isosceles, and angles ABC and BAC are equal. The sum of all three angles is 180.
Where y is angle ABC
180 = 2y+x
y = 90-x/2

Do you have the answer?


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