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Maths - Circle Theorems |
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| Apr24-05, 04:15 AM | #1 |
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Maths - Circle Theorems
Hi,
I am really confused with circle theorems, attached is a diagram and I need to find out ABC and CBO. I have worked out that angle ACB is x degrees, and also know that angle OAC is equal to angle OBC. But I don't know how to work out the what either are Thanks Graham |
| Apr24-05, 04:17 AM | #2 |
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Is this something to do with opposite angles on a cyclic quadratic add up to 180?
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| Apr24-05, 04:17 AM | #3 |
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If youcan post it on the web somewhere, we'd be able to see it before tomorrow. It has to be pre approved.
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| Apr24-05, 04:19 AM | #4 |
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Maths - Circle Theorems |
| Apr24-05, 04:31 AM | #5 |
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Do you know anything specific about the inscription of the triangle in the circle? I want to say that the arcs between A B and C are 120 degrees, but I can't tell if thats whatits supposed to be. |
| Apr24-05, 04:36 AM | #6 |
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Find in terms of X, expressions for the angles:
- ABC - CBO The points A,B, and C lie on the centre circle O. |
| Apr24-05, 04:47 AM | #7 |
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Since AC = BC, the triangle ABC is isosceles, and angles ABC and BAC are equal. The sum of all three angles is 180.
Where y is angle ABC 180 = 2y+x y = 90-x/2 Do you have the answer? |
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