Flow of electrons (electricity/mechanics problem)

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SUMMARY

The discussion focuses on calculating the speed of electrons and their flow rate in a television picture tube. The speed of an electron just before it strikes the screen is determined to be 6.49 x 107 m/s, derived from equating potential energy to kinetic energy using a potential difference of 12,000 volts. The number of electrons arriving at the screen per second is calculated to be approximately 2.85 x 1014 electrons, utilizing the formula for electric current (I = Q/t) and the charge of an electron (1.6 x 10-19 C).

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  • Understanding of electric potential and kinetic energy principles
  • Familiarity with the formula for electric current (I = Q/t)
  • Knowledge of the charge of an electron (1.6 x 10-19 C)
  • Basic mechanics involving nonrelativistic motion
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  • Study the relationship between potential difference and kinetic energy in charged particles
  • Learn about electric current and its calculation in circuits
  • Explore the implications of electron flow in vacuum tubes and cathode ray tubes
  • Investigate the effects of high voltage on electron behavior and emission of x-ray photons
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Physics students, electrical engineers, and anyone interested in the mechanics of electron flow and its applications in electronic devices.

benji
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So here's the problem:

In a television picture tube, elections are accelerated from rest through a potential difference of 12,000 volts and move toward the screen of the tube. When the electrons strike the screen, x-ray photons are emitted. Treat the elections nonrelativistically and determine:

a) the speed of an electron just before is strikes the screen

b) the number of electrons arriving at the screen per second if the flow of electrons in the tube is 0.01 coulomb per second

I've already figured part a by setting potential energy (equalling charge multiplied by potential difference) equal to kinetic energy. My answer is 6.49*10^7 m/s.

However, b is where I'm having trouble. I don't know how to go about it. Could someone please point me in the right direction?
 
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Since each electron has a charge of its own, the total charge for n number of electrons is the n times the charge of the electron
that is [tex]Q = Ne[/tex]
 


In order to solve part b, we need to use the formula for electric current, which is defined as the rate of flow of charge. This can be written as I = Q/t, where I is the current in amperes, Q is the charge in coulombs, and t is the time in seconds.

Since we are given that the flow of electrons in the tube is 0.01 coulomb per second, we can plug this into the formula and solve for the current:

I = 0.01 C/s

Next, we need to find the charge on each electron. This can be calculated using the formula Q = ne, where n is the number of electrons and e is the charge of an electron (1.6*10^-19 C).

We know that the potential difference is 12,000 volts, which is equivalent to 12,000 joules per coulomb. So, we can set up an equation using the potential energy formula and solve for n:

12,000 J/C = (1/2)mv^2

n * 1.6*10^-19 C = (1/2) * m * (6.49*10^7 m/s)^2

Solving for n, we get n = 2.85*10^14 electrons.

Now, we can plug this value into the formula for current and solve for the number of electrons arriving at the screen per second:

I = 0.01 C/s = (2.85*10^14 electrons)/t

Solving for t, we get t = 2.85*10^16 seconds.

Therefore, the number of electrons arriving at the screen per second is approximately 2.85*10^14 electrons.
 

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