Need help with Fluid Dynamics Problem

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SUMMARY

The discussion centers on a fluid dynamics problem involving two cylinders, L and R, with cross-sectional areas A and 2A, respectively. The initial water level in cylinder L is H, while cylinder R is empty. The problem requires finding the time at which the water levels equalize after connecting the cylinders with a tube of cross-section a. The user applies mass conservation and Bernoulli's Theorem, leading to a differential equation that yields an imaginary solution for the water level in cylinder R, indicating a conceptual error in the approach.

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maverick280857
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Hi everyone

I have a relatively simple fluid dynamics problem I need some help with:

We have two cylinders L and R of crossectional areas A and 2A respectively. Initially, the level of water in X is H and Y is empty. At t = 0, the two cylinders are joined at the bottom by a tube of cross-section a (after a hole of the same cross-section is opened in each cylinder). Find the time at which the water level is equal in both cylinders.

This is what I've done so far.

Denote the water levels in the left (L) and right (R) cylinders by [itex]y_{L}[/itex] and [itex]y_{R}[/itex] respectively. So [itex]y_{L}(t=0) = H[/itex] and [itex]y_{R}(t=0) = 0[/itex].

Mass conservation (or continuity equation) leads to [itex]AH = Ay_{L} + 2Ay_{R}[/itex] or equivalently [itex]H = y_{L} + 2y_{R}[/itex]. This gives [itex]0 = \dot{y_{L}} + 2\dot{y_{R}}[/itex].

Applying Bernoulli's Theorem to two points at the surface of each meniscus, we get

[itex]P_{atm} + \frac{1}{2}{\rho v_{1}^2} + \rho g h_{1} = P_{atm} + \frac{1}{2}{\rho v_{2}^2} + \rho g h_{2}[/itex]

where [itex]P_{atm}[/itex] is the atmospheric pressure, [itex]\rho[/itex] is the density of water, [itex]v_{1} = -\dot{y_{L}}[/itex], [itex]v_{2} = \dot{y_{R}}[/itex], [itex]h_{1} = y_{L}[/itex], [itex]h_{2} = y_{R}[/itex].

Hence,

[itex]\frac{1}{2}{\rho \dot{y_{L}}^2} + \rho g y_{L} = \frac{1}{2}{\rho \dot{y_{R}}^2} + \rho g y_{R}[/itex]

After simplifying a bit, this gives a differential equation in [itex]y_{R}[/itex] with the boundary conditions [itex]y_{R}(t=0) = 0[/itex] and [itex]y_{R}(t = T) = \frac{H}{3}[/itex] where H/3 is the equilibrium height of water level (in each cylinder--this follows from the mass conservation equation above) and T is the time when this happens.

Now, if you try this out you get an imaginary (and therefore ridiculous) solution for [itex]y_R[/itex]. As far as I think, my algebra is okay so there must be a conceptual fault somewhere. I would be very grateful if someone could offer some advice.

PLEASE NOTE: This is not a homework problem but I couldn't think of a better place to post it on PF.

Thanks and cheers,
Vivek

EDIT: The answer should involve [itex]a[/itex], the cross-section of the orifice, but it doesn't in my case.
 
Last edited:
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Hi again

I checked my TeX code (it seems okay to me) but most of it isn't working...

Cheers
Vivek

EDIT: Its working now :-D
 
Last edited:
I figured it out thanks.
 

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