- #1
mark9159
- 13
- 0
im having trouble setting my TI-83 Plus into "degree mode" so i can't seem to get the answers for these problems...im probably doing them wrong too
A material has an index of refraction of 1.75. What is the critical angle for this material?
Sin(critical angle)=1/n, n being the index of refraction
how would i set up the formula? (critical angle)= Sin(n) ?? I am so confused
and
The critical angle for cubic zirconium is 29.2º. What is the index of refraction?
so...Sin(29.2º)= 1/n?...
my answer for this question is 2.049, rounded to 2.05
thank you,
mark
A material has an index of refraction of 1.75. What is the critical angle for this material?
Sin(critical angle)=1/n, n being the index of refraction
how would i set up the formula? (critical angle)= Sin(n) ?? I am so confused
and
The critical angle for cubic zirconium is 29.2º. What is the index of refraction?
so...Sin(29.2º)= 1/n?...
my answer for this question is 2.049, rounded to 2.05
thank you,
mark