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Length contraction and time dilation |
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| Apr29-05, 01:18 PM | #1 |
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Length contraction and time dilation
I'm having trouble understanding how length contracts while time dilates when the 2 equations in the lorentz transformation dealing with these are nearly identical (which makes me think that length and time should transform in the same way).
Thanks in advance. |
| Apr29-05, 03:30 PM | #2 |
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| Apr29-05, 04:31 PM | #3 |
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[tex]l = L/\gamma[/tex] [tex]t = \gamma T[/tex] So, one equation involves dividing by [tex]\gamma[/tex] and the other involves multiplying by it. |
| Apr29-05, 06:13 PM | #4 |
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Length contraction and time dilation
JesseM,
But the difference comes about because, as you said, "L represents the length of a ruler" and "T represents the time elapsed between two events". Those aren't analagous. If you want to talk about "the length of the ruler" then you have to talk about "the tick rate of the clock". If you want to talk about "the time elapsed between two events" then you have to talk about "the distance between two events. Using your notation, if you let L and l be the measured distances between two events and let T and t be the measured times elapsed between the two events, then if L = gamma*l, T = gamma*t. The symmetry between space and time in relativity is one of the the most beautiful relationships in all physics. And the way the "time dilation" and "length contraction" formulas are constructed is, in my opinion, an abomination. They're a relentless source of confusion, to say nothing of all the "I've proven that Einstein was wrong" claims that they've spawned. Anyway, that's what I think. |
| Apr29-05, 07:04 PM | #5 |
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The way it's normally used, the time dilation formula is only meant to apply when you have two events which happen at the same location but different times in one frame, and you want to know the time between them in another frame. And the length contraction formula isn't even meant to give you the distance between the same two events in different frames, instead it tells you that if you look at the distance L between two events representing the position of the front and back of an object "at the same moment" in its own rest frame, then if you want to know the distance l between two events representing the position of the front and back of the object "at the same moment" in a different frame (since the frames disagree about simultaneity, these can't be the same two events), the relation between the distances is given by l = L/gamma. |
| Apr29-05, 08:03 PM | #6 |
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x' = x - vt t' = t you get this, x' = Y(x - Bct) ct' = Y(ct - Bx) Don't you think that's great? |
| Apr29-05, 08:55 PM | #7 |
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| Apr30-05, 12:32 AM | #8 |
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I cant help to point out again that Euclidean relativy so much simplifies this that I can even explain it to a complete layman. It is not a denial of classical relativity but just an alternative mathematical framework that replaces the Minkowski framework. I know even of a teacher who uses it in his class against mainstream approval because he noticed that then at last his students began to show an understanding of relativity.
In Euclidean relativity Lorentz transformations become rotations in SO(4). A moving rod has rotated towards the negative axis of the time dimension according to an observer at rest. This rotation gives the rod a length component in the timedimension, hence the non-simultaneity of points on the rod. The spatial length component decreases, hence its length contraction in space. Something similar happens to the 4D velocity vector c of the rod. It can be decomposed in a spatial velocity component and a time velocity component . The latter decreases with increasing spatial velocity, hence the slowdown of clocks in moving objects. This animated GIF file shows how it works: animation |
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