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1+2+3+4+...=1/12? proof 
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#1
Feb2014, 02:32 AM

P: 400

I've see this neat proof:
http://www.youtube.com/watch?v=Ed9m...ion_3085392237 (for some reason the youtube tag didn't work in preview...) And now I don't see how what I've learned about series convergence is true... I've been told that if [itex]a_n > b_n \forall n[/itex] then [itex] \sum a_n > \sum b_n [/itex] therefore, if [itex] \sum b_n [/itex] is divergent then, [itex] \sum a_n [/itex] must be too. Also, If the partial sum diverges, the series is said to be divergent, isn't it? And what about [itex] a_n \neq 0 [/itex] for n that tends to infinity? So many ways I could show this series diverges, yet he show it's equal to 1/12??? Where am I, or is he, wrong? 


#2
Feb2014, 02:57 AM

P: 18

I think this cannot be true. The sum of all natural numbers up to N equals (as also shown in the end of the video) ## N(N+1)/2 ##. This obviously goes to infinity as N goes to infinity. And of course there is also no way how strictly positive numbers can add up to give a negative result.



#3
Feb2014, 03:01 AM

P: 400

That's what I was saying :)
So where is he wrong? 


#4
Feb2014, 03:13 AM

P: 533

1+2+3+4+...=1/12? proof
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