Solving Angular Rotation w/ Constant Acceleration - Emilie

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Homework Help Overview

The discussion revolves around a problem in angular motion, specifically involving constant angular acceleration and the calculation of initial angular velocity. The scenario describes a potter's wheel with a known angular acceleration and the total angle rotated over a specific time interval.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between angular acceleration, angular displacement, and angular velocity. There are attempts to apply kinematic equations for rotational motion, with some questioning the correctness of their methods and assumptions.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the problem. Some have expressed confusion about the application of formulas and the relationships between the variables involved. There is no explicit consensus on the correct approach yet.

Contextual Notes

Participants are working within the constraints of a textbook problem, which may limit the information available for solving the question. There is also a noted misunderstanding regarding the application of angular kinematic equations.

~angel~
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I've been trying to do this question in the textbook, but I can't seem to get the answer.

Emilie's potter's whel rotates with a constant 2.25 rad/s^2 angular acceleration. After 4 seconds the wheel has rotated through an angle of 60.0 rad. What was hte angular velocty of the wheel at the beginning of the 4.00 second interval.

I thought I could use a = (w2-w1)/ (t2-t1), but I end up with 6 as my answer, which is incorrect.

Thank you in advance.
 
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Perhaps this thread will help.
 
Ok, I've got it. But why is my method incorrect?
 
~angel~ said:
Ok, I've got it. But why is my method incorrect?

Because:

[tex]\omega_2\ne\frac{\Delta \theta}{\Delta t}=15\ rad/s[/tex]

Actually,

[tex]\bar{\omega}=\frac{\omega_2+\omega_1}{2}=\frac{\Delta \theta}{\Delta t}[/tex]
 

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