
#1
Feb2514, 08:03 AM

P: 27

The graph of potential energy of two nucleons shows a minima at 100 MeV,but the binding energy of a deuterium nucleus is close to just 1 MeV.
Since binding energy is the energy required to rip apart the nucleus ,hypothetically,should the two values not be same? 



#2
Feb2514, 08:17 AM

P: 368

Can you show the graph?
In general the binding energy of two nucleons depends on the nucleon type (eg nn and pp are not possible).... For having a bound state you need E<0. 



#3
Feb2514, 08:27 AM

P: 27

Please see the attachment.




#4
Feb2514, 09:07 AM

P: 368

Binding Energy
I guess that this graph wants to describe the fact that the nucleons will prefer existing within the nuclei radius, rather than going too far away or falling on each other




#5
Feb2514, 09:27 AM

P: 1,244





#6
Feb2514, 05:19 PM

Mentor
P: 10,809

The minimum potential is just a lower bound for the binding energy  and you would need particles of "infinite" mass to approach this value. The real nucleons will form some (3dimensional) wavefunction similar to the electron, and have an energy corresponding to a solution of the Schrödinger equation (ignoring relativistic effects).



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