Pushing a 6kg Pic Against a Wall: Find the Force Needed

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SUMMARY

The discussion focuses on calculating the force required to push a 6kg picture against a wall to prevent it from sliding. The static friction coefficient between the wall and the picture is 0.7, while the kinetic friction coefficient is 0.3. The formula used to determine the necessary force (F) is F = mg/U, where m is the mass (6kg), g is the gravitational acceleration (9.8 m/s²), and U is the static friction coefficient (0.7). The resulting force required to keep the picture from sliding is 84N.

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nix
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i don't understand this..the way the forces go:frown:
if someone could show me how to do it and the steps..that would be great:
The static friction coefficient btw a wall and a pic is 0.7 while the kinetic one is 0.3. By what force shoudl one push the 6kg pic against the wall so that it will not slide?What if he/she pushed the pic with a force making an angle of 30 degrees to the horizontal (both cases)[?]


thanx!
 
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If you draw a freebody diagram, you will find that for the picture to not slide,
U*F=m*g
must be true. To solve for F:
F=mg/U
m=6kg
g=9.8m/s^2
U=.7
So F=84N
But I can't be sure because I don't know if I understand what you mean and I don't know what you mean by the second part of the question.
 
thanx for the help
i think i can take it from here :smile:
 

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