Is the Speed Calculation for an Artificial Satellite Accurate?

  • Thread starter Thread starter bullroar_86
  • Start date Start date
Click For Summary
SUMMARY

The speed calculation for an artificial satellite traveling at an altitude of 230 km above the Earth's surface is confirmed to be accurate at v = 3 x 10^4 m/s. The gravitational acceleration at this altitude is g = 9.0 m/s², and the Earth's radius is 6370 km. To determine the time taken for one complete revolution, the centripetal acceleration must be provided by gravitational force, which can be calculated without knowing the satellite's mass. The discussion concludes that using the known velocity and radius allows for straightforward calculation of the orbital period.

PREREQUISITES
  • Understanding of gravitational acceleration and its effects on orbital motion
  • Knowledge of centripetal acceleration and its relationship to circular motion
  • Familiarity with basic physics formulas for velocity and period of revolution
  • Concept of kinetic energy in the context of satellite motion
NEXT STEPS
  • Calculate the orbital period of a satellite using the formula T = 2πr/v
  • Explore the relationship between gravitational force and centripetal acceleration
  • Investigate the effects of altitude on satellite speed and gravitational force
  • Learn about the principles of satellite motion and orbital mechanics
USEFUL FOR

Students and professionals in physics, aerospace engineering, and anyone interested in satellite dynamics and orbital calculations.

bullroar_86
Messages
30
Reaction score
0
Would you agree with the calculation reagarding the speed of an artificial satelite, v = 3 x 10^4 m/s, assuming that it is traveling at an altitude h = 230 km above the Earth's surface where g = 9.0 m/s^2. ?

The radius of the Earth is 6370 km.

Also, how long would it take for the satelite to complete one revolution?


not sure where to start here.. any help would be great
 
Physics news on Phys.org
Which force must provide the satelite's centripetal acceleration, and how does that force look like in the case where you are 230 km above the Earth's surface?
 
U can find its KE,but u still would have to know its mass in order to determine its speed (the modulus of its tangential velocity).

If u know the velocity & assume the trajectory is a circle whose radius u already know,then u can easily find the period,wouldn't u say...?

Daniel.

EDIT:Arildno's approach is the right one.You needn't the mass in this case...
 

Similar threads

Replies
5
Views
3K
Replies
5
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
37
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
35
Views
4K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K