How many ways to get a Four of a kind?

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Homework Help Overview

The discussion revolves around calculating the number of ways to obtain specific poker hands, including Four of a Kind, Full House, and Two Pairs, as well as determining combinations for obtaining pairs with different numbers of dealt cards.

Discussion Character

  • Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate combinations for various poker hands using combinatorial formulas. They express uncertainty about the correctness of their calculations and seek validation from others.

Discussion Status

Some participants provide affirmations regarding the original poster's calculations, indicating a level of confidence in the approaches taken. However, explicit consensus on the correctness of the answers has not been reached.

Contextual Notes

The original poster poses multiple questions related to different poker hand combinations and the number of ways to achieve them, indicating a focus on combinatorial analysis within the context of poker rules.

gillgill
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Poker hands...

1. How many ways are there to obtain these three highly-rated combinations below?
a. Four of a kind. -Four cards of the same rank and one other card

b. Full House. -Three cards of the same rank and two cards both of another rank. ( A triple, or three of a kind, and a pair.)

c. Two pairs. -Two pairs of cards of two distinct ranks and a fifth card of another rank.

2. Suppose you play a game in which only three cards are deal: How many ways are there to obtain one pair?

3. Suppose four cards are dealt. How many ways are there to obtain one pair?

am i doing these correctly?
1a. 13C1 X 48C1 = 624
b.13C1 X 4C3 X 12C1 X 4C2 = 3744
c.13C2 X 4C2 4C2 44C1 = 123,552

2.13C1 X 4C2 X 12C1 X 4C1 = 3744

3. 13C1 X 4C2 X 12C1 X 4C1 X 11C1 X 4C1 = 164736

am i right?
 
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Hmm, a flash review of your answers suggests to me you are correct

-- AI
 
You seem to know what you're doing gillgill. So why the doubt?
 
thanks...
 

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