# Strength In Single Crystals

by edcurrymuncher
Tags: crystals, single, strength
 P: 5 I am no authority on the subject but I recently did a problem very similar to the one you're working on. And I believe the poster above me is correct in their assertion. In my problem, the applied load was [120], slip plane (111) and slip direction [110]. Something helpful (which I learned from my professors) is to draw the cubic cell with the indicated plane and directions. This will help you get a feel of what $\phi$ and $\lambda$ look like. In addition to load and slip directions, you will also need to determine the direction perpendicular to the slip plane. The key, however, is to use the dot product to find cos$\phi$ and cos$\lambda$. In order to do this you will need to treat the three key directions as vectors. Hopefully this was of some help to you.