What is the confidence interval for a 100 ohm resistor with 10% tolerance?

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The 95% confidence interval for a 100 ohm resistor with a 10% tolerance is calculated using the formula: 100 ohms ± 1.96(5.10204 ohms). The standard deviation (sigma) is determined to be approximately 5.10204 ohms, leading to a confidence interval of 90 ohms to 110 ohms. The calculation utilizes a k-value of 1.96 from the z-table for a 95% confidence level. This analysis confirms that the tolerance is correctly applied as 10 ohms, representing 10% of the nominal resistance.

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vptran84
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What is the 95% confidence interval for 100 ohm resister with 10% tolerence?

Here is my work so far, can someone please tell me if I am doing it wrong or right? Thank you in advance.

from table 95%: k = 1.96
100 * 0.1( which is the 10% tolerance) = 10

10 / sigma >= 1.96
Sigma <= 5.10204

confidence interval limits:
100ohm +- 1.96(5.10204ohms) = 100ohm +- 10ohms
 
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Maybe my definition of tolerance is wrong, but isn't 1 sigma = 10% * 100ohms = 10 ohms?

A 95% confidence interval would then be +/- 1.96 sigma.
 

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