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Required Torque on Motor 
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#1
Apr2214, 08:05 AM

P: 6

Hi I am trying to work out the torque required to rotate an object from 0 to 1RPM in 1 second (1 second accelerate to 1RMP) , its working in time laps so very small movement is required.
The diameter of the gear is 30mm and the diameter of the shaft is 10mm, the object on top weights 20kg it's sitting on a low friction bearing. So far I have Torque = F x r r = radius of the cylinder = 0.005 Force = mass x acceleration where mass = 20kg accel = velocity/time velocity = r x ω (rotational speed) where ω at 1RPM = 6.28 rad/sec So v = 0.005 x 6.28 = 0.0314 m/s Therefore accel = 0.0314/t Therefore T = 12 x 0.031/t x 0.005 = 0.186/t Nm I know there is alot more to this but I am very new to this and out of my comfort zone in terms of engineering knowledge (I'm a product designer) , I've mainly been following pre worked examples I've found online. Would really appreciate some help and guidance. 


#2
Apr2314, 09:44 PM

P: 25

Seems like you got the correct answer, So whats the problem?



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