# Pressure question

by A.J.710
Tags: pressure
 P: 28 I am sitting in the library just thinking and I have a general question about pressure. Basically think of the problem as a 5 gallon bucket filled with water and a water tight circle of some sort sitting on top. Now say I stand on that circle and the force is exerted downward compressing the water. Now for simplistic reasons if there is a hole in the side wall at the bottom of the bucket with a 1" surface area, would the pressure of the water coming out of that whole be the sum of the force exerted by me standing on top and the water inside the bucket? The water pressure inside is minimal. I just basically want to know if my body weight of 200 pounds divided by the surface area of the hole 1" would make the pressure coming out of the hole 200 PSI plus the minimal water pressure inside. Thats what I am trying to get at. Is the pressure directly transferred from my weight on top to the hole on the bucket or is there some sort of loss somewhere in the system where there won't be that type of drastic build up in pressure when I stand on top of the system. Thanks
P: 558
 Quote by A.J.710 I am sitting in the library just thinking .
Libraries can be a dangerous place for thinking. Be careful.

 Quote by A.J.710 ...would the pressure of the water coming out of that whole be the sum of the force exerted by me standing on top and the water inside the bucket? .
No.

 Quote by A.J.710 The water pressure inside is minimal. .
Actually it has enough pressure to support your weight and the weight of the water itself.

 Quote by A.J.710 I just basically want to know if my body weight of 200 pounds divided by the surface area of the hole 1" would make the pressure coming out of the hole 200 PSI plus the minimal water pressure inside.
No, the water flowing out would effectively have the same pressure as the atmosphere.

 Quote by A.J.710 Is the pressure directly transferred from my weight on top to the hole on the bucket or is there some sort of loss somewhere in the system where there won't be that type of drastic build up in pressure when I stand on top of the system.
There will be a build up of pressure in the water to support your weight which will continue to exist until all the water has left the bucket.
P: 28
 Quote by paisiello2 Libraries can be a dangerous place for thinking. Be careful. No. Actually it has enough pressure to support your weight and the weight of the water itself. No, the water flowing out would effectively have the same pressure as the atmosphere. There will be a build up of pressure in the water to support your weight which will continue to exist until all the water has left the bucket.
Is there some way to calculate the water pressure coming out of that 1" hole then?

 P: 558 Pressure question I already stated above it is effectively at atmospheric pressure.
P: 28
But with my weight on top of it wouldn't more water be forced out? Similar to a big balloon filled with water. If it is opened and the water is freely flowing out, when someone squeezes it it starts to shoot the water harder. Thats what I mean here. If the water is constantly being compressed down and the only source of escape is through that hole why wouldn't the pressure build up? It doesn't have to be just my weight. If there is a bucket of water and a 1" hole near the base and there is a huge hydraulic system pushing it down more water is going to come out as the force increases, correct?

 Quote by paisiello2 I already stated above it is effectively at atmospheric pressure.
 P: 1,478 The pressure of the water at the bottom of the bucket is ρgh without you standing on it. Once you stand on the platform, the extra pressure at the bottom of the bucket will be your weight divided by the area of the platform, in addition to that from the height of the water column. That is the pressure at the bottom of the bucket. If you open the hole, the water will exit to atmospheric pressure. One cannot physically speak of the pressure of the water coming out of the hole. One would ask what is the extra velocity of the water coming out of the hole due to increased pressure, or what is the increase in water flow coming out of the hole due to increased pressure.
P: 28
I don't understand what you guys mean by atmospheric pressure. I am thinking of head pressure. For example if a tube was connected to the hole and extended upwards. The water will travel up the tube to the height of the rest of the water. Now if I stand on the bucket that water will be forced even farther upwards. Isn't that a reading of PSI of the water in the tube or is it something different?

 Quote by 256bits The pressure of the water at the bottom of the bucket is ρgh without you standing on it. Once you stand on the platform, the extra pressure at the bottom of the bucket will be your weight divided by the area of the platform, in addition to that from the height of the water column. That is the pressure at the bottom of the bucket. If you open the hole, the water will exit to atmospheric pressure.
 P: 558 Atmospheric pressure = 101.3kPA or 14.7psi. http://en.wikipedia.org/wiki/Atmospheric_pressure There's a subtle but important difference between the point just inside the bucket before it exits the hole and the point just outside the hole as the water flows out. Inside the bucket, the water velocity is negligibly small but the pressure is the total of the weight of the water and of you standing on it. Outside the bucket, the water is flowing very fast but the pressure has now dropped to atmospheric pressure. If you attach a tube to the hole and extend it upwards, all you have done is effectively move the hole to the top of the tube. The hole and the top of the tube are both at atmospheric pressure. The only difference is that once the weight of the column of water matches the weight of the water remaining in the bucket plus your own weight, then the water column will come to rest.