# Charge Conjugate of the Vacuum

by ChrisVer
Tags: charge, conjugate, vacuum
 P: 1,021 What is the result of the charge conjugation acting on the state of vacuum? $C|0>=...$ I have two intuitive problems.... If I see the vacuum as something which has no particles, then the charge conjugate would have to lead in the vacuum itself... $C|0>=|0>$ However, if I think of the vacuum as the state on which creation operators act to create states, the above result doesn't seem correct. For example I would guess that the C acting on the vacuum would create a new vacuum: $C|0>=|\bar{0}>$ On which now the creation operators will act destructively (because they would have to create particle in the antiparticle vacuum- the exact opposite of destruction operator acting on the initial vacuum).... On the other hand the destruction operators will bring out antiparticle states.... I am seeing the creation operators as particles and destruction operators as antiparticles, since they propagate (in momentum space) to opposite directions... Which is correct (I already know it's the 1st) and more importantly, why?