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Integration by trig. substitution

 
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May16-05, 07:59 PM   #1
mad
 

Integration by trig. substitution


Hello everyone
I have an exam tomorrow and I would really appreciate if someone could tell me what I did wrong with this exercice. I did it on paper and I scanned it. Here is the link to the scan:

The answer in the book is sqrt(x^2 + x +5/4) + 2ln(sqrt(x^2 + 2x + 2) + x +1) + C

http://img223.echo.cx/img223/8425/problem490012al.jpg

It is hosted on imageshack.us
download it and open it in windows so you can change the zoom size for better viewing

Thanks a lot in advance !!
 
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May16-05, 08:02 PM   #2
 
If u = x + 1, where does u + 1 come from? That is just the first thing I saw, it may lead to your other problems.
 
May16-05, 08:04 PM   #3
 
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It should be "u+2" in the numerator after doing the first sub.

Daniel.
 
May16-05, 08:29 PM   #4
mad
 

Integration by trig. substitution


Quote by dextercioby
It should be "u+2" in the numerator after doing the first sub.

Daniel.
Woops. Was this the only problem? I think this only changes the arctg from the final answer and not the ln(..) of the answer. I hate when this type of error happens..
 
May16-05, 08:40 PM   #5
 
When translating from theta back to x, you mistranslated sec(t).

Next to the triangle you have

[tex] sec(\theta) = \frac{1}{\cos(\theta)} = \frac{1}{u} [/tex]

cos(theta) is not u, try looking at it again.
 
May16-05, 08:45 PM   #6
mad
 
Quote by whozum
When translating from theta back to x, you mistranslated sec(t).

Next to the triangle you have

[tex] sec(\theta) = \frac{1}{\cos(\theta)} = \frac{1}{u} [/tex]

cos(theta) is not u, try looking at it again.
Thanks a lot :)
 
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