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Derivation of E=mC2 
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#1
May1705, 10:03 PM

P: 55

¿How did Einstein derived that E=mC2?. ¿ Can I find an english translation of his original paper?.



#2
May1705, 10:12 PM

P: 53

http://www.fourmilab.ch/etexts/einstein/E_mc2/e_mc2.pdf (there is translated in english the second article Einstein published in Annalen der physik about special relativity thanks dex, i missed last in german) 


#3
May1705, 10:31 PM

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P: 11,915

It was his second article on SR in 1905 and the IVth overall in that year.
http://www.aip.org/history/einstein/chron1905.htm Daniel. 


#4
May1805, 10:16 PM

P: 55

Derivation of E=mC2
thanks Rebel and dextercioby for the required information



#5
May1905, 01:08 AM

P: 100

You can simply take this integral and you'll get [tex] E = mc^2 [/tex]
[tex] \int^c_0{P dv} ; [/tex] where [tex] P = mv\gamma [/tex] and [tex] \gamma = \frac{1}{\sqrt{1  (\frac{v}{c})^2}} [/tex] [tex] \int^c_0 {\frac{mv}{\sqrt{1  (\frac{v}{c})^2}} dv = mc^2 [/tex] 


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