# Derivation of E=mC2

by Iraides Belandria
Tags: derivation, emc2
 P: 100 You can simply take this integral and you'll get $$E = mc^2$$ $$\int^c_0{P dv} ;$$ where $$P = mv\gamma$$ and $$\gamma = \frac{1}{\sqrt{1 - (\frac{v}{c})^2}}$$ $$\int^c_0 {\frac{mv}{\sqrt{1 - (\frac{v}{c})^2}} dv = mc^2$$