## Redox Relapse

We need to know what the products of KI + H2O in ionic form.

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 Blog Entries: 9 Recognitions: Homework Help Science Advisor The reaction should be $$2KI+H_{2}O\rightleftharpoons K_{2}O+2HI$$ which in ionic form $$2K^{+}+2I^{-}+H^{+}+OH^{-}\rightleftharpoons 2K^{+}+O^{2-}+2H^{+}+2I^{-}$$ I don't see any redox here... Daniel.
 THe labis on oxidation reduction. It says that ppt turns pink in the presence of hyrdroxide ions and the starch will turn black/blue in the presence of molecular iodine. We figured that this meant that in the equation that this meant in the products their will be a hydroxide ions and an I molecule. We thought that the answer you gave us was right but our teacher said that we were closer when we showed him KI + H2O--> OH + K + I2 + H

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## Redox Relapse

Yes,i didn't think of that option.There it is.Can u find the coefficients by accomplishing the electron transfer ?

$$aK^{+}+bI^{-}+cH^{+}+dOH^{-}\rightleftharpoons eK^{+}+fOH^{-}+gI_{2}+h H_{2}\uparrow$$

Daniel.

 yeah we should be able to, um what are the a,b,c,d,e,f,g for?
 Blog Entries: 9 Recognitions: Homework Help Science Advisor Coefficents,like 1,2,1/2,3/2,3. So who's getting oxidated and who's getting reduced...? Daniel.
 umm I havent done it yet;P
 Blog Entries: 9 Recognitions: Homework Help Science Advisor It's not funny.If u haven't done redox reactions in school,why do you bother with this problem...? Daniel.
 Me thinks something is a miss here. Was it hydroxide or peroxide ?
 it was hydroxide

 Quote by airheadan THe labis on oxidation reduction. It says that ppt turns pink in the presence of hyrdroxide ions and the starch will turn black/blue in the presence of molecular iodine.
OK what is ppt ?

 Admin Short for precipitate. dextercioby: no O(2-) in solution! NEVER! airheadan: what exactly was in the solution (list everything)? What was the pink precipitate? Best, Borek -- Chemical calculators for labs and education http://www.chembuddy.com BATE - pH calculations, titration curves CASC - concentration conversions, solution preparation
 the ppt is phenalthailene...and the reaction is K + I + H2O --> KOH + I + H

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 teacher said that we were closer when we showed him KI + H2O--> OH + K + I2 + H
Alright, I would imagine that this is a simple dissociation reaction, $$KI_{(s)}+H_2O \rightarrow K^{+}_{(aq)}+I^{-}_{(aq)}$$

The starch test will not work without molecular iodide however, I2. You'll need both I2 and I-, for the iodine complex involving I3-.

 Quote by airheadan the ppt is phenalthailene...and the reaction is K + I + H2O --> KOH + I + H
OK I'm highly dyslexic, but did you mean phenolphthalein ? There still is something a miss here (like what would oxidize the I-).

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