How is a Galvanometer Converted into an Ammeter Using a Shunt?

In summary: This fact indicates that the resistance of current meter should be as small as possible.So we can use the low resistance wire that is directly wound on the coil.In summary, the shunt resistor helps to reduce the current the galvanometer can measure, allowing for measurement of higher currents.
  • #1
Hardik Batra
130
5
To make ammeter,
Resistance of proper small value is joined in parallel to the coil of galvanometer.This resistance is called a shunt.


For smaller resistance value,
We can not use the smallest resistance wire that is directly wound on coil of galvanometer so the resistance will become minimum.?
 
Physics news on Phys.org
  • #2
hi there Hardik

do you understand what the shunt resistance does ?
I suspect not :wink:

the coil resistance on its own may give a full scale reading of say 100mA
but what if you wanted to read 1A or 10A or 100A ?

so for example if you want to read 10A full scale, and the coil can only read 100mA full scale, then the shunt must pass the other 9.9 Amps (9900 mA)

Here's an excellent article on the use and calculating of shunt resistors ...
http://www.allaboutcircuits.com/vol_1/chpt_8/4.html

cheers
Dave
 
  • #3
In (fig. a) we want to measure current passing through the resistance R in a circuit shown in fig.

I=V/R

In (fig. b) galvanometer is joined in series with resistance R, as shown in fig.

In such connection resistance G of the galvanometer is added in the circuit

and as the total resistance of the circuit is changed the value of current to be measured itself is changed

I = V/(R+G)

Thus the true value of current is not obtained.

this fact indicates that the resistance of current meter should be as small as possible.

So we can't use the low resistance wire that directly wound on coil so that you will get directly,

I = V/R.
 

Attachments

  • ammeter.jpg
    ammeter.jpg
    9 KB · Views: 500
  • #4
Hardik Batra said:
To make ammeter,
Resistance of proper small value is joined in parallel to the coil of galvanometer.This resistance is called a shunt.For smaller resistance value,
We can not use the smallest resistance wire that is directly wound on coil of galvanometer so the resistance will become minimum.?
As with all Engineering, it's a matter of compromise, using the materials that are available.
The galvanometer needs to be sensitive enough to detect very small currents. The movement needs to be very light, so it responds quickly to a short pulse. That forces the use of thin wire which will burn out with higher currents. So you are stuck with a resistance that is not that low (you need sufficient turns on the armature to get a deflection).

For measuring higher values of current, the shunt dissipates most of the energy so the coil won't burn out.
 
  • Like
Likes 1 person
  • #5


The use of a shunt to convert a galvanometer into an ammeter is a common practice in the field of electrical engineering. By adding a shunt in parallel to the galvanometer's coil, the overall resistance of the circuit is reduced, allowing for a larger current to flow through the ammeter. This is necessary because the coil of a galvanometer is typically designed to have a high resistance, which is suitable for measuring small currents. However, when measuring larger currents, the high resistance of the galvanometer would limit the amount of current that can flow through it and potentially damage the instrument. By using a shunt, we can effectively decrease the overall resistance of the circuit and allow for accurate measurement of larger currents. This is a practical and efficient way to transform a galvanometer into an ammeter.
 

1. What is a galvanometer and how does it work?

A galvanometer is a device used to measure small electric currents. It works by using a coil of wire that is suspended in a magnetic field. When a current passes through the coil, it creates a magnetic field that interacts with the existing magnetic field, causing the coil to rotate. The amount of rotation is proportional to the strength of the current.

2. How is a galvanometer converted to an ammeter?

To convert a galvanometer to an ammeter, a shunt resistor is added in parallel with the galvanometer. This shunt resistor allows most of the current to bypass the galvanometer, so that only a small portion of the current passes through the coil and causes it to rotate. By measuring the voltage drop across the shunt resistor, the total current can be calculated and displayed on a scale.

3. What is the difference between a galvanometer and an ammeter?

A galvanometer is a device used to measure small currents, while an ammeter is used to measure larger currents. The main difference between the two is the addition of a shunt resistor in an ammeter, which allows for the measurement of higher currents without damaging the delicate components of the galvanometer.

4. What are the units of measurement for a galvanometer and an ammeter?

The units of measurement for a galvanometer and ammeter are both amperes (A), which is the SI unit for electric current. However, depending on the sensitivity and range of the instrument, the units may be expressed as milliamperes (mA) or microamperes (μA) for a galvanometer, and amperes or kiloamperes (kA) for an ammeter.

5. What are some common applications of a galvanometer converted to an ammeter?

A galvanometer converted to an ammeter is commonly used in electrical and electronic circuits to measure the current flowing through various components. It is also used in industries such as telecommunications, power generation, and automotive to monitor and control currents in different systems and processes. In scientific research, galvanometers converted to ammeters are used in experiments involving small currents, such as in electrochemistry and electrophysiology.

Similar threads

Replies
6
Views
1K
Replies
13
Views
2K
  • Other Physics Topics
Replies
7
Views
17K
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
3K
  • Electrical Engineering
Replies
26
Views
6K
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
3K
Back
Top