- #1
gloo
- 261
- 2
I know that there is the equation to capture work of falling water using dams (power= head*flow*gravity constant*efficiency).
But let's just say that there is an empty basin in the middle of a large body of water that is 100 meters deep. If the basin is 30m * 30m and we have a conduit that is open to the body of water at the top and extends down to the bottom of the basin; is it correct to say that if the water is allowed to fill the basin to the top by allowing water to fall down the conduit and fill the basin that the work done from the falling water is:
work=Force *distance
30m*30m*100m *1000kg/cubic meter *9.81m/second square*100m
=88,290,000,000 Newton meters (joule)
So if there is an energy capturing device (assume 100 percent efficiency), it would capture all the energy of 88,290,000,000 Joules?
Sorry for the amateur assumptions and calculations :(
G
But let's just say that there is an empty basin in the middle of a large body of water that is 100 meters deep. If the basin is 30m * 30m and we have a conduit that is open to the body of water at the top and extends down to the bottom of the basin; is it correct to say that if the water is allowed to fill the basin to the top by allowing water to fall down the conduit and fill the basin that the work done from the falling water is:
work=Force *distance
30m*30m*100m *1000kg/cubic meter *9.81m/second square*100m
=88,290,000,000 Newton meters (joule)
So if there is an energy capturing device (assume 100 percent efficiency), it would capture all the energy of 88,290,000,000 Joules?
Sorry for the amateur assumptions and calculations :(
G