- #1
Fetch
- 26
- 0
Homework Statement
Starting from rest, a particle moves along an x-axis from point A to point B with constant acceleration a1 = 2.20 m/s2 through displacement d1 = 500 m. Then it slows at constant acceleration a2 through displacement d2 = 300 m from point B to point C where it is again at rest. If the total time is 60.0 s, what is the value of a2?
Homework Equations
Kinematics Equations
V = Vo + at
(X -Xo) = Vt - (1/2)at^2
V^2 = Vo^2 +2a(X - Xo)
(X - Xo) = Vot + (1/2)at^2
(X - Xo) = (1/2)Vo + V)t
The Attempt at a Solution
So I layed out a chart with my variables with respect to A1 and A2.
I tried a a couple things. Solving for the time, then subtracting that time from 60 to use the value for the A2 portion of the kinematics. Kept getting -0.401 as the acceleration whenever I solved for the time. Tried using the final velocity (A1) as the initial velocity (A2) and didn't have much luck.
Not sure if this is a sig fig thing or if I'm just missing something obvious. Not entirely sure. I'd appreciate the answer + explanation. I've got 3 attempts leftover and would rather not risk losing points on a homework problem. Help please.