RadiationX
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i'm trying to find what the intermediate steps were used in solving this differential equation:
[tex]y'' + y' -3y =0[/tex]
[tex]m=\frac{-1\pm\sqrt{13}}{2}[/tex] now we have
[tex]y=C_1e^{\frac{-.5+\sqrt{13}}{2}}t + C_2e^{\frac{-.5 -\sqrt{13}}{2}}t[/tex]
note that the .5 are 1\2. i couldn't get the latex for this to work
[tex]y'' + y' -3y =0[/tex]
[tex]m=\frac{-1\pm\sqrt{13}}{2}[/tex] now we have
[tex]y=C_1e^{\frac{-.5+\sqrt{13}}{2}}t + C_2e^{\frac{-.5 -\sqrt{13}}{2}}t[/tex]
note that the .5 are 1\2. i couldn't get the latex for this to work