Register to reply 
Here i am again newtons second lawby badman
Tags: newtons 
Share this thread: 
#1
Jun605, 12:18 AM

P: 57

Consider another special case in which the inclined plane is vertical (\theta=\pi/2). In this case, for what value of m_1 would the acceleration of the two blocks be equal to zero?
Express your answer in terms of some or all of the variables m_2 and g. a good point in the direction will help 


#2
Jun605, 12:28 AM

HW Helper
P: 2,279

Draw a Free Body Diagram for each box, and i recommend for the inclined box to have a system of coordinates at the angle theta with respect to the horizontal.



#3
Jun605, 07:11 AM

P: 12

The acceleration of the two blocks be equal to zero when the weight of Block 1 is equals to the tension of string. Then, there is no net force acting on Block 1, hence Block 2, the velocity is uniform or equals to zero.



#4
Jun605, 09:43 AM

P: 57

Here i am again newtons second law
thanks guys. can you help me with a another problem.
Now imagine two points, Q and P, that divide the rope into segments L, M ,and R. View Figure The rope remains stationary. Assume that segment L exerts a force of magnitude F_LM on segment M. What is the magnitude F_RM of the force exerted by segment R on segment M? Give your answer in terms of F_LM and constants such as g. shouldnt the force acting on segment R be equal to the force segment M exerted on it but in opposite direction? i inputed F_lm *G but it said i was missing a multiplicative factor? 


#6
Jun605, 11:03 AM

P: 57

whoops i was thinking of another answer to another problem i had. sorry bout that



#7
Jun705, 09:58 AM

P: 57

nvm, i had another question but i already solved it



#8
Jun705, 11:03 AM

P: 57

heres another i cant seem to right
The diagram below shows a block of mass m=2.0\; \rm kg on a frictionless horizontal surface, as seen from above. Three forces of magnitudes F_1 = 4.0\;{\rm N}, F_2 = 6.0\;{\rm N}, and F_3 = 8.0\;{\rm N} are applied to the block, initially at rest on the surface, at angles shown on the diagram. View Figure In this problem, you will determine the resultant (total) force vector from the combination of the three individual force vectors. All angles should be measured counterclockwise from the positive x axis (i.e., all angles are positive). this is the question Calculate the magnitude of the total resultant force \vec{F}_{\rm r} = \vec{F}_1+ \vec{F}_2 +\vec{F}_3 acting on the mass. Express the magnitude of the resultant force in newtons to two significant figures. i already know the formula and that i need to break this down into compenents. for each force vector. the confusing thing is the angles, that i need. this is basically how i set it up. Fx1= N*cos155 fy1=N*sin155 fx2 and fy2 i cant seem to get fx3=N*cos325 fy3=Ncos325 are the angles right, i cant seem to figure out the angle for the vector F_2 


#9
Jun705, 12:18 PM

Mentor
P: 41,316

F1 is at 25 degrees (not 155); F2 is at 325 degrees; F3 is at 180 degrees (it points in the x direction, which is 180 degrees from the +x direction). 


#10
Jun705, 01:22 PM

P: 57

thanks doc.



Register to reply 
Related Discussions  
Newtons Third Law  Introductory Physics Homework  9  
Psi to Newtons  Classical Physics  6  
Newtons second law  Introductory Physics Homework  4  
Newtons 2nd law  Introductory Physics Homework  17  
Newtons third law?  Introductory Physics Homework  2 