Khan
I'm having some problems expanding i^i, could anyone help? I know it becomes a real number somehow, and I'm familiar with the e^(i * pi) expansion, but is the i^i done in the same way?
The Taylor series expansion for i^i can be derived using Euler's formula and DeMoivre's Theorem. By substituting x = π/2 into Euler's formula, we find that i = e^(iπ/2). Raising both sides to the power of i results in i^i = e^(-π/2), which evaluates to approximately 0.207879576. This confirms that i^i is indeed a real number.
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