Reduced Circumference: Schwarzschild vs Kerr Metric

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SUMMARY

The discussion clarifies that the r-coordinate in the Schwarzschild metric represents the reduced circumference, while in the Kerr metric, it does not. Instead, the r-coordinate in the Kerr metric requires a coordinate transformation to derive the reduced circumference, represented as \inline{R(r)^2 d{\phi}^2}. This transformation indicates a different physical interpretation of the r-coordinate in the context of rotating black holes.

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  • Understanding of general relativity concepts
  • Familiarity with Schwarzschild and Kerr metrics
  • Knowledge of coordinate transformations in physics
  • Basic mathematical skills for interpreting metric equations
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  • Research the implications of the Kerr metric on black hole physics
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Moore1879
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Okay, I understand that the r-coordinate in the Schwarzschild metric represents the reduce circumference. My problem is that the r-coordinate in the Kerr metric is NOT the reduced circumference! What is it? Somebody, please answer this as quickly and as painlessly as possible!
Thank You
 
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Right, it is not. What is it? Sorry, I don’t know... I guess that if you make a coordinate change in a way that you get [tex]\inline{R(r)^2 d{\phi}^2}[/tex] then [tex]\inline{R}[/tex] will be the reduced circumference for [tex]\inline{\phi}}[/tex]. May be this can give you a hint about a possible physical meaning of [tex]\inline{r}[/tex].
 

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