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RLC question (complicated) |
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| Jun16-05, 09:59 AM | #1 |
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RLC question (complicated)
I find this question very hard and i could not work out the answers, i have looked on the internet for forumals but they don't seem to work ??
Anyone got any methods to work through the question ??? I found a website that is about RLC series circuits but looking into it, it really confuses me with all the equations: http://www.tpub.com/neets/book2/4l.htm An RLC series circuit has a resonant frequency of 1.2kHz and Q factor at resonance of 50. If the impedance of the circuit is 75 ohms calculate the values of: a. the inductance vaule b. the capacitance value c. the bandwidth d. the lower and upper half-power frequencies e. the vaules of the circuit impedance at the half power frequencies. Thanks |
| Jun16-05, 01:31 PM | #2 |
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The resonant frequency of a LC circuit is:
[tex]\omega_0 = \frac{1}{\sqrt{LC}}[/tex] And the quality factor is: [tex]Q = \omega_0 RC[/tex] Since it is given a real value for the impedance, we must assume that this value is calculated at the resonant frequency. Z = R. So, you know ω0, Q and R. You have two equations and two unknowns: L and C. |
| Jun21-05, 04:51 AM | #3 |
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ok here is the equation i used
Q = XL/R = XC/R Q x R = XL 50 x 75 = 3750 ohms Q x R = XC 50 x 75 = 3750 ohms then just use XL = 2pie FL and XC = 1 / 2pie FC transpose that !!!! L = 2pie F / XL C = 1 / 2pie F XC But one more question, what equation can i use to get the lower and upper half power frequencies ??? |
| Jun21-05, 09:53 AM | #4 |
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RLC question (complicated)[tex]Q = \frac {\omega_0}{\omega_2 - \omega_1}[/tex] Where [tex]\omega_0[/tex] is the resonant frequency and [tex]\omega_1[/tex], [tex]\omega_2[/tex] the half power frequencies. |
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