Max Height of Rolling Hoop w/Radius 0.13m and Mass 8.1kg

Click For Summary
SUMMARY

The maximum height reached by a thin hoop with a radius of 0.13 m and mass of 8.1 kg, rolling without slipping at a velocity of 4.0 m/s up an incline of 33 degrees, can be determined using the conservation of energy principle. The total mechanical energy is conserved, where the sum of rotational kinetic energy and linear kinetic energy equals the potential energy at the maximum height. The moment of inertia for the hoop is calculated as (1/2)Mr², allowing for the simplification of the mass variable in the calculations.

PREREQUISITES
  • Understanding of conservation of energy principles
  • Knowledge of rotational kinetic energy calculations
  • Familiarity with potential energy concepts
  • Ability to apply moment of inertia formulas for rigid bodies
NEXT STEPS
  • Calculate the maximum height using the conservation of energy formula
  • Explore the effects of different angles of inclination on maximum height
  • Investigate the impact of varying mass and radius on the hoop's motion
  • Learn about the dynamics of rolling motion and its applications
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of rolling objects and energy conservation principles.

melissa_y
Messages
17
Reaction score
0
thin hoop of radius r = 0.13 m and mass M = 8.1 kg rolls without slipping across a horizontal floor with a velocity v = 4.0 m/s. It then rolls up an incline with an angle of inclination theta = 33o. What is the maximum height h reached by the hoop before rolling back down the incline
 
Physics news on Phys.org
Show us what you have done...
 
melissa_y said:
thin hoop of radius r = 0.13 m and mass M = 8.1 kg rolls without slipping across a horizontal floor with a velocity v = 4.0 m/s. It then rolls up an incline with an angle of inclination theta = 33o. What is the maximum height h reached by the hoop before rolling back down the incline

do it using conservation of energy...

rotational K.E + linear K.E= P.E( at the height reached on the inclined plane)
take moment of inertia of a ring=1/2mr sqr abt the central axis while calculating rotational K.E.
u will straightaway get the ans by cancelling out M
 
Last edited:

Similar threads

  • · Replies 18 ·
Replies
18
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
3K
Replies
4
Views
2K
Replies
5
Views
4K
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K