Calculating Max Speed of a Particle on String

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SUMMARY

The maximum speed of a particle on a string in a simple harmonic transverse wave is calculated using the formula 4A/T, where A represents the amplitude and T denotes the period of the wave. This conclusion is derived from the relationship between velocity, frequency, and wavelength, specifically v = fλ, where frequency (f) equals 1/T and wavelength (λ) equals 2A. The maximum particle speed is achieved when the cosine function equals one, resulting in the formula ωA = 2πf*A = 2πA/T. Thus, the maximum speed is effectively doubled to 4A/T due to the particle completing two cycles in one period.

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  • Basic calculus for differentiation (∂s/∂t)
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For a simple harmonic transverse wave that is propagating along a string toward the right, how is maximum speed of a particle on the string calculated?
Is it

4A/T
If A=amplitude and T=Period?
 
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vroman said:
For a simple harmonic transverse wave that is propagating along a string toward the right, how is maximum speed of a particle on the string calculated?
Is it

4A/T
If A=amplitude and T=Period?
displacement = s(x,t) = A*sin(ωt - kx + φ)
particle speed = v(x,t) = ∂s(x,t)/∂t = (ωA)*cos(ωt - kx + φ)
max particle speed (when cos=1) = ωA = 2πf*A = 2πA/T
 


Yes, the maximum speed of a particle on a string can be calculated using the formula 4A/T, where A is the amplitude of the wave and T is the period of the wave. This formula is derived from the relationship between velocity, frequency, and wavelength in a wave, which is v = fλ. In a simple harmonic transverse wave, the frequency (f) is equal to 1/T, and the wavelength (λ) is equal to 2A. Therefore, the maximum velocity can be calculated as v = (1/T)(2A) = 2A/T. However, since the particle on a string undergoes two complete cycles (one full oscillation) in one period, the maximum speed is doubled to 4A/T. This formula can be used to calculate the maximum speed of any particle on a string for a given amplitude and period.
 

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