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[SOLVED] Why zero slope limit is point particle limit? |
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| Jul1-05, 04:28 AM | #1 |
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[SOLVED] Why zero slope limit is point particle limit?
<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no,location=no, scrollbars=yes,resizable=yes,status=no,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>Hi,\n\nWhat is the easiest and/or best argument on that the string zero slope\nlimit alpha\' ->0 is the point particle limit?\n\nThanks,\nKang-Sin\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>Hi,
What is the easiest [itex]and/or[/itex] best argument on that the string zero slope limit [itex]\alpha' ->0[/itex] is the point particle limit? Thanks, [itex]Kang-Sin[/itex] |
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| Jul4-05, 10:47 AM | #2 |
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<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no,location=no, scrollbars=yes,resizable=yes,status=no,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>On Fri, 1 Jul 2005 05:28:33 -0400, ughacks@gmail.com <ughacks@gmail.com> wrote:\n> Hi,\n>\n> What is the easiest and/or best argument on that the string zero slope\n> limit alpha\' ->0 is the point particle limit?\n\nalpha\' is inversely proportional to the string tension. Sending it to\nzero makes the string shrink to a point. Furthermore, all vibrations\nof the string become infinitely costly in energy. In the quantum\ntheory, the masses of all the string modes are proportional to\n1/alpha\' so all but the massless modes decouple from the theory and\nyou are left only with the massless point-particles (hopefully, you\'ve\nalready gotten rid of the tachyon).\n\nRobert\n\n\n--\n..oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo .oOo.oOo.oO\nRobert C. Helling School of Science and Engineering\nInternational University Bremen\nprint "Just another Phone: +49 421-200 3574\nstupid .sig\\n"; http://www.aei-potsdam.mpg.de/~helling\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>On Fri, 1 Jul 2005 05:28:33 [itex]-0400,[/itex] ughacks@gmail.com <ughacks@gmail.com> wrote:
> Hi, > > What is the easiest [itex]and/or[/itex] best argument on that the string zero slope > limit [itex]\alpha' ->0[/itex] is the point particle limit? [itex]\alpha'[/itex] is inversely proportional to the string tension. Sending it to zero makes the string shrink to a point. Furthermore, all vibrations of the string become infinitely costly in energy. In the quantum theory, the masses of all the string modes are proportional to [itex]1/\alpha'[/itex] so all but the massless modes decouple from the theory and you are left only with the massless point-particles (hopefully, you've already gotten rid of the tachyon). Robert -- ..oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.o Oo.oOo.oO Robert C. Helling School of Science and Engineering International University Bremen print "Just another Phone: [itex]+49 421-200[/itex] 3574 stupid [itex].sig\n";[/itex] http://www.aei-potsdam.mpg.de/~helling |
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