## [SOLVED] Why zero slope limit is point particle limit?

<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no,location=no, scrollbars=yes,resizable=yes,status=no,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>Hi,\n\nWhat is the easiest and/or best argument on that the string zero slope\nlimit alpha\' -&gt;0 is the point particle limit?\n\nThanks,\nKang-Sin\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Hi,

What is the easiest $and/or$ best argument on that the string zero slope
limit $\alpha' ->0$ is the point particle limit?

Thanks,
$Kang-Sin$

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On Fri, 1 Jul 2005 05:28:33 $-0400,$ ughacks@gmail.com wrote: > Hi, > > What is the easiest $and/or$ best argument on that the string zero slope > limit $\alpha' ->0$ is the point particle limit? $\alpha'$ is inversely proportional to the string tension. Sending it to zero makes the string shrink to a point. Furthermore, all vibrations of the string become infinitely costly in energy. In the quantum theory, the masses of all the string modes are proportional to $1/\alpha'$ so all but the massless modes decouple from the theory and you are left only with the massless point-particles (hopefully, you've already gotten rid of the tachyon). Robert -- ..oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.oOo.o Oo.oOo.oO Robert C. Helling School of Science and Engineering International University Bremen print "Just another Phone: $+49 421-200$ 3574 stupid $.sig\n";$ http://www.aei-potsdam.mpg.de/~helling