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image Pauli Spin Matrices in Domain Walls Share It Thread Tools image
Old Jul9-05, 01:50 PM                  #1
trpublicaddress@yahoo.com

trpublicaddress@yahoo.com is
Posts: n/a
Pauli Spin Matrices in Domain Walls

<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','to olbar=no,location=no,scrollbars=yes,resizable=yes, status=no,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usene t ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>Hi. This is my first visit to sci.physics.researh. Hope this is an\nappropriate place for the following post.\n\nI\'m trying to follow a paper about spin flip across domain walls.\nThe magnetization within the wall is M=(cosx,sinx,0) and I\'m trying to\nunderstand how the author arrived at the spin component of the\nHamiltonian (he offers no explanation, so I think it\'s pretty simple).\nHe has a constant (-.5*exchange energy) times the matrix\n\n[[sinx cosx\ncosx, sinx]]\n\nI looked at another paper, where it gives this term as a constant times\nmagnetization dotted with the Pauli spin matrices. However, when I\nperform the same operation with the above M, I don\'t get the same value\nas the first paper. The problem I think that I\'m having is that I\ndon\'t really understand the pauli matrices (my background in quantum is\nvirtually nonexistent). It is not clear to me what physically\ndistinguishes the x,y,z matrices, or indeed what makes these axes\nnon-arbitrary. All I know about the region is that electrons are\ninjected into the domain wall with spins parallel to the wall (pointed\nin the y direction, as they travel in the x direction) and that the\nmagnetization within the wall is as defined above. I don\'t understand\nhow this defines axes for the pauli matrices and thus how he arrives at\nthe matrix in the Hamiltonian at all. I\'ve read a couple books where\nthey say the matrices are defined so as to diagonalize S^2 and Sz, but\nI don\'t have any idea what that means.\n\nExplanations, clues, or pointers to relevant sources appreciated.\n\nThanks in advance.\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>Hi. This is my first visit to sci.physics.researh. Hope this is an
appropriate place for the following post.

I'm trying to follow a paper about spin flip across domain walls.
The magnetization within the wall is LaTeX Code: M=(cosx,sinx,0) and I'm trying to
understand how the author arrived at the spin component of the
Hamiltonian (he offers no explanation, so I think it's pretty simple).
He has a constant (-.5*exchange energy) times the matrix

[[sinx cosx
cosx, sinx]]

I looked at another paper, where it gives this term as a constant times
magnetization dotted with the Pauli spin matrices. However, when I
perform the same operation with the above M, I don't get the same value
as the first paper. The problem I think that I'm having is that I
don't really understand the pauli matrices (my background in quantum is
virtually nonexistent). It is not clear to me what physically
distinguishes the x,y,z matrices, or indeed what makes these axes
non-arbitrary. All I know about the region is that electrons are
injected into the domain wall with spins parallel to the wall (pointed
in the y direction, as they travel in the x direction) and that the
magnetization within the wall is as defined above. I don't understand
how this defines axes for the pauli matrices and thus how he arrives at
the matrix in the Hamiltonian at all. I've read a couple books where
they say the matrices are defined so as to diagonalize LaTeX Code: S^2 and Sz, but
I don't have any idea what that means.

Explanations, clues, or pointers to relevant sources appreciated.

Thanks in advance.

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Old Jul11-05, 02:44 PM                  #2
J. J. Lodder

J. J. Lodder is
Posts: n/a
Re: Pauli Spin Matrices in Domain Walls

<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','to olbar=no,location=no,scrollbars=yes,resizable=yes, status=no,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usene t ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>&lt;trpublicaddress@yahoo.co m&gt; wrote:\n\n&gt; Hi. This is my first visit to sci.physics.researh. Hope this is an\n&gt; appropriate place for the following post.\n&gt;\n&gt; I\'m trying to follow a paper about spin flip across domain walls.\n\nsnip\n\n&gt; I don\'t understand\n&gt; how this defines axes for the pauli matrices and thus how he arrives at\n&gt; the matrix in the Hamiltonian at all. I\'ve read a couple books where\n&gt; they say the matrices are defined so as to diagonalize S^2 and Sz, but\n&gt; I don\'t have any idea what that means.\n&gt;\n&gt; Explanations, clues, or pointers to relevant sources appreciated.\n\nMore complicated motions of spins\nare best described in terms of the polarization vector.\n\nMerzbacher\'s Quantum Mechanics\nmay be a good place for you to get started,\n\nJan\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky><trpublicaddress@yahoo.com> wrote:

> Hi. This is my first visit to sci.physics.researh. Hope this is an
> appropriate place for the following post.
>
> I'm trying to follow a paper about spin flip across domain walls.


snip

> I don't understand
> how this defines axes for the pauli matrices and thus how he arrives at
> the matrix in the Hamiltonian at all. I've read a couple books where
> they say the matrices are defined so as to diagonalize LaTeX Code: S^2 and Sz, but
> I don't have any idea what that means.
>
> Explanations, clues, or pointers to relevant sources appreciated.


More complicated motions of spins
are best described in terms of the polarization vector.

Merzbacher's Quantum Mechanics
may be a good place for you to get started,

Jan

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Old Jul13-05, 12:52 AM                  #3
Gerard Westendorp

Gerard Westendorp is
Posts: n/a
Re: Pauli Spin Matrices in Domain Walls

<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','to olbar=no,location=no,scrollbars=yes,resizable=yes, status=no,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usene t ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>trpublicaddress@yahoo.com wrote:\n\n[..]\n\n&gt; I\'m trying to follow a paper about spin flip across domain walls.\n&gt; The magnetization within the wall is M=(cosx,sinx,0) and I\'m trying to\n&gt; understand how the author arrived at the spin component of the\n&gt; Hamiltonian (he offers no explanation, so I think it\'s pretty simple).\n&gt; He has a constant (-.5*exchange energy) times the matrix\n&gt;\n&gt; [[sinx cosx\n&gt; cosx, sinx]]\n&gt;\n&gt; I looked at another paper, where it gives this term as a constant times\n&gt; magnetization dotted with the Pauli spin matrices. However, when I\n&gt; perform the same operation with the above M, I don\'t get the same value\n&gt; as the first paper.\n\n\nSpinors are a bit like polarization vectors, but a bit weirder.\nThey are weirder, because they are not like objects we can\nsee around us in the macroscopic world. There are rules to\nextract data from spinors, and these rules generally involve\nthe Pauli matrices. For example, if you want to know something\nabout the x-component of the polarization vector, you have to take\nthe x-Pauli matrix, operate it on the spinor, and then take the\ninner product of the result and the original spinor. This\nwill spit out a number, which is the x-component you want to\nknow.\n\n\nI think the interaction Hamiltonian will be something like\n\n(B.sigma) Psi\n\nFill that in, and you get:\n\n[[0 cosx-isinx\ncosx+isinx 0]]\n\nmultiplied by Psi\n\n\nThis is different from you matrix, but I don\'t see why.\n\n\nGerard\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">&nbsp;&nbsp;View this Usenet post in original ASCII form </a></div><P></jabberwocky>trpublicaddress@yahoo.com wrote:

[..]

> I'm trying to follow a paper about spin flip across domain walls.
> The magnetization within the wall is LaTeX Code: M=(cosx,sinx,0) and I'm trying to
> understand how the author arrived at the spin component of the
> Hamiltonian (he offers no explanation, so I think it's pretty simple).
> He has a constant (-.5*exchange energy) times the matrix
>
> [[sinx cosx
> cosx, sinx]]
>
> I looked at another paper, where it gives this term as a constant times
> magnetization dotted with the Pauli spin matrices. However, when I
> perform the same operation with the above M, I don't get the same value
> as the first paper.



Spinors are a bit like polarization vectors, but a bit weirder.
They are weirder, because they are not like objects we can
see around us in the macroscopic world. There are rules to
extract data from spinors, and these rules generally involve
the Pauli matrices. For example, if you want to know something
about the x-component of the polarization vector, you have to take
the x-Pauli matrix, operate it on the spinor, and then take the
inner product of the result and the original spinor. This
will spit out a number, which is the x-component you want to
know.


I think the interaction Hamiltonian will be something like

LaTeX Code: (B.\\sigma) \\Psi

Fill that in, and you get:

[[0 cosx-isinx
cosx+isinx 0]]

multiplied by LaTeX Code: \\Psi


This is different from you matrix, but I don't see why.


Gerard

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