## What holds an atom together?

I have a Mathematics teacher, who enjoys asking questions to student(s) on the subjects of Physics and Chemistry. Firstly, What holds an atom together? According to gravity, matter that orbits an object, if its terminal velocity slows down, the gravitational pull should pull the electron into the nucleus. Why isn't this the case for atoms?

Also, I read in another discussion, (which I can't find) about the formula(s) for why electrons aren't pulled into the atom, and can freely jump to the different shelfs...

Help!
 I can't give you a definitive answer, but I can try to point you in the right direction. It's generally accepted that there are four fundamental forces in the universe: 1. Gravitational Attraction 2. Electromagnetism 3. Strong Nuclear Force 4. Weak Nuclear Force I'm not sure how much help this will be, but maybe it'll shed some light.
 electrons arent pulled to the atom because of coulumb's law. but i dont know what holds atom. But before i dig information to answer this, what is the deep-ness of atom are you looking at?

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## What holds an atom together?

The -vely charged electran attracted towards positively charged nucleus but this force is not bringing it closer but utilised to rotate it round the nucleus, like a tension force is required to whirl a sone in circular path, such required force is called centripetal force and here the electric attractive force is behaving as c.p. force. Gravitationl force in this case is very very small and we are not considering it,
 An electrically neutral atom consists of 'electrons' and a 'nuclei consisting of nuetrons and protons'.The amount of negative charge carried by the elctrons outside the nucleus , is balanced by same amount of positive charge carried by the protons inside the nucleus.Therefore , as a whole atom is neutral.In nuetral state, atom is stable.And the electrons can be excited to higher states if sufficient energy is given to them , that is giving energy to the atom would make it unstable.Now in normal state , nucleus has a fixed '+ve charge' inside it which results in a constant force on an electron at a distance from the nucleus. This force of attraction between the nucleus and electron acts as centripetal force which acts on electron in the direction of the nucleus, as a result electron moves around in a circle.However if this centripetal force is increasing with time , the electron will accelerate while moving in circle , as a result an 'accelerating electron emits radiation' , and as it emits radiation loses energy and goes in a spiral path toward sthe nucleus, but this does not happen , because Bohr placed the electrons in energy-stable shells (like you study n=1,2 .. for hydrogen). There is one more theoretical reason why an electron cannot fall into the nucleus.As per Heisenberg's Uncertainity Principle, if an electron is found to be insid ethe nucleus , this means we are accurately knowing its position , this would result in tremendous gain in momentum for electron and it would shoot itself out of the nucleus. BJ
 If you are talking about the nucleus of the atom, then the strong and weak nuclear forces keep things in place. In larger atoms with more protons, the neutrons provide some displacement between the atoms so that thier electrical charges do not cause the protons in the nucleus to split into multiple nuclei. If this occured naturally fission would be happening all over the place. I guess it'd be a great source of power but first you'd have to stop everything from getting blown up. Anyways if your diving deeper into the question as what holds a proton together, well then you've got me. I know these sub atom "particles" are composed of even smaller things called quarks. In specific I believe a proton is classified as a baryon meaning its composed of 3 quarks. I think it is made of two up quarks and 1 down quark. Each up quark has a charge of +2/3 and the down quark has a charge of -1/3, so the total charge adds up to +1 (no suprise). There are 4 other "flavor" of quarks. They are called strange, charm, top, bottom, and the two mentioned - up and down. There are other physical aspects of quarks such as "color" charge as opposed to electrical charge only. While quarks establish a nice basis for particles, I believe if you keep breaking these even smaller particles down, you will keep ending up with more and more particles. Think of these things as a tournament layout. An atom as the champion, the neutron, proton, and electron in the finals bracket. Perhaps quarks in the semi-final bracket and so on. The more fundamental we try to get, the more complicated things become as we need to add dimensions onto physical quantities to remain consistent. I believe no such thing as a discrete particle exists. I think everything even at the quantum level is composed of field interactions. It would seem to me that in order to be consistent with the notion of continuity, that it is not possible to instantly go from white to black. Meaning, the boundary between two infinitely small points can be split into even a smaller jump over which there has to be a "grey" zone.
 To add more, there are certain 'allowed' orbits for electrons such that angular momentum of electron in these orbits is integral multiple of h/2(pie) . In these permitted orbits , even if electrons accelerate donot radiate EM Energy , but they do radiate radiations when they jump from one shell to another. BJ
 Recognitions: Gold Member In the nucleus of an atom, the 'strong' nuclear force holds the protons and neutrons together. The 'weak' force is responsible for radioactive decay. When it comes to electrons, they are first off to be considered as noncorporeal negative charges as opposed to particles. Electron 'orbitals' define the area in which the quantum fluctuations regarded as 'electrons' are most likely to be found. Even given the ambiguity of their physical status, electrons are restricted to particular orbital distances dependent upon their energy. The change from one orbital to the next involves the absorbtion or ejection of a photon corresponding to the energy differential between the 2 orbitals. On this scale, gravity is totally inconsequential. And incidentally, 'terminal velocity' refers to the point at which opposing forces such as air resistance balance out gravity in a free-falling body. It has no proper usage in nuclear physics.

 Quote by Dr.Brain There is one more theoretical reason why an electron cannot fall into the nucleus.As per Heisenberg's Uncertainity Principle, if an electron is found to be insid ethe nucleus , this means we are accurately knowing its position , this would result in tremendous gain in momentum for electron and it would shoot itself out of the nucleus.
I don't think this is correct. Heisenberg's Uncertainty Principle formulates a fundamental relation for measuring, it shows with what degree of uncertainty one can measure. The product of the uncertainty in position and the uncertainty in momentum have to be equal or higher than a certain constant. That means that if you accurately know the position of an electron you inaccurately know its momentum. There is however no "gain in momentum" (as you stated). Just because you know the position of an electron (for example) very well that doesn't mean it picks up speed or gets more massive. Correct me if I'm wrong.

 Quote by TheSpeed=DUCK! ...if its terminal velocity slows down, the gravitational pull should pull the electron into the nucleus. Why isn't this the case for atoms?
Well, you're implying there that the electron loses speed: why is that?
The thing is that in the classical theory an accelerated electron emits photons and thereby loses energy (and therefore speed). The motion of an electron in an atom is an accelerated motion, because it's circular. Therefore, the classical theory states that the electron should "fall" into the nucleus. As we all know, there is a better theory for very small things, the quantum theory. Electrons, neutrons and protons are quantum objects. This means that they can behave wave-like and particle-like.
The real "surprise" now is not only the way the electrons stay "in orbit" (these orbital lines are a visualization and should not be thought of as what the electrons do; it's just a model), but also the way the nucleus holds together. The nucleus of an atom is very, very small compared to the size of the atom. There's a tremendous charge density inside the nucleus in comparison to the rest. Now, the electrostatic forces should force the protons to leave the nucleus in different directions, but that doen't usually happen (fortunately) so there are other forces that hold the nucleus together: the nuclear forces (they have been mentioned). These forces act only on very small distances (electrostatic forces theoretically have an infinite reach), but in many cases it's enough to compensate for the electrostatic ones and hold the nucleus together. In some other cases it isn't: Consider an atom with many nuclear particles, many protons. They all repell each other over a distance of several protons, that means that they don't only repell their direct neighbours. The nuclear forces can't reach that far and so what happens is called a decay: the nucleus can't be kept together and the atom either emits some particles or splits up.
For all these phenomena the effects from the electron clouds (the electron orbitals) are neglectable. The gravitational model for the electrons going around the nucleus like the earth around the sun just can't explain it all anymore.

 I don't think this is correct. Heisenberg's Uncertainty Principle formulates a fundamental relation for measuring, it shows with what degree of uncertainty one can measure. The product of the uncertainty in position and the uncertainty in momentum have to be equal or higher than a certain constant. That means that if you accurately know the position of an electron you inaccurately know its momentum. There is however no "gain in momentum" (as you stated). Just because you know the position of an electron (for example) very well that doesn't mean it picks up speed or gets more massive. Correct me if I'm wrong. Quote:

"What keep an electron form falling in? . This principle: If they were in the nucleus, we would know their position precisely, and the uncertainity principle would then require that they have a large momentum , i.e instantly gaining a very high kinetic energy.With this energy , they would break away from the nucleus.They make a compromise: they leave themselves a little room for this uncertainity and then jiggle with certain amount of motion"

-Richard P Feynman
 As per modern QM , electron is no more a dot of mass , rather its a cloud and electron can be found in this cloud. These clouds have a random presence all over the atom and confining them to a finite boundary of a nucleus is precisely knowing position of electron in this cloud, not allowed.

 Quote by cliowa I don't think this is correct. Heisenberg's Uncertainty Principle formulates a fundamental relation for measuring, it shows with what degree of uncertainty one can measure. The product of the uncertainty in position and the uncertainty in momentum have to be equal or higher than a certain constant. That means that if you accurately know the position of an electron you inaccurately know its momentum. There is however no "gain in momentum" (as you stated). Just because you know the position of an electron (for example) very well that doesn't mean it picks up speed or gets more massive. Correct me if I'm wrong.
Not so sure. Any particle's uncertainty in momentum would, I assume, include 0 momentum. As the uncertainty in momentum increases, the most likely range will also shift higher up (think of a bell curve being stretched as an analogy). If you take the most likely momentum as being as good an estimate of actual momentum as we can have, this value would presumably increase as certainty in position increases.

I asked a question on this a while back. If you have an electron at a given distance r (ignore uncertainty for now) from the nucleus then that electron has a certain potential. As the distance decreases, the potential decreases and so the momentum increases. The total of kinetic and potential energy will presumably remain the same (pending emission of photon energy). When you take into account that photons of strict energies only may be emitted, so an electron cannot radiate it's kinetic energy all the way down to the nucleus, it makes perfect sense that an electron in the nucleus will have enough momentum to escape the nucleus, otherwise it would never have been elsewhere. I didn't get any response from this, so thoughts here would be welcome.

 Quote by Dr.Brain "What keep an electron form falling in? . This principle: If they were in the nucleus, we would know their position precisely, and the uncertainity principle would then require that they have a large momentum , i.e instantly gaining a very high kinetic energy.With this energy , they would break away from the nucleus.They make a compromise: they leave themselves a little room for this uncertainity and then jiggle with certain amount of motion" -Richard P Feynman
This was the quote I started a thread about, and it seemed an awful lot of people didn't take everything within it quite seriously. For instance, we would not know the precise position of the electron in a nucleus if we did not know the precise position of the nucleus itself. Secondly, as pointed out earlier, a high uncertainty in momentum does not necessitate a high momentum, only a more likely high momentum. Thirdly, none of it stops an electron 'falling in' (to my knowledge)... only from keeping it in. All of which confused me greatly until various PF members set me on the right track.

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 Quote by Dr.Brain As per modern QM , electron is no more a dot of mass , rather its a cloud and electron can be found in this cloud. These clouds have a random presence all over the atom and confining them to a finite boundary of a nucleus is precisely knowing position of electron in this cloud, not allowed.
But don't you see that there is a major problem with what you are quoting from Feynman?

You are saying that we cannot confine an electron (or anything else for that matter) with the size of a nucleus because the confinment size is too small so much so that it will have an uncertainty in momentum that is very large. Fine, let's go with that.

However, look at the protons and neutrons themselves! They ARE confined to a spatial size THAT small! How come they don't fly off?

The problem in quoting someone without understand the PRINCIPLE that is being illustrated is that you only see the tail end of the animal without seeing what the whole animal looks like. The uncertainty principle, DISPITE its name, is NOT a principle, but rather a CONSEQUENCE. If you solve a simple 3D coulombic potential, the LOWEST ground state energy wavefunction will produce EXACTLY the condition that is described by the uncertainty relations. You can obtain this even if you are ignorant of the HUP. It just drops onto your lap when you solve for it. It means that with JUST the coulombic potential ALONE, you have reached the limit to how small you can confine the electrons IF you care to look at it from the HUP point of view. But again, even if you're ignorant of the HUP, the solution you got already tells you that there's NO LOWER ground state than what you already have without having to invoke the HUP.

So what's going on with the protons and neutrons? Why are they able to be confined to a region that an electron can't? If you simply apply the HUP principle here, you'll run into trouble because it is already contradictory. So the answer has to be to go back to the very beginning and look at the Hamiltonian/Schrodinger equation to be solved. Here, the potential term isn't just simply coulombic, but contains the strong interactions. This then modifies the potential well that produces the bound state and you have to re-solve the "wavefunction" all over again. This will then produces a NEW ground state, etc etc...

Be very careful when you apply something without knowing what's under the covers.

Zz.
 if speed=duck is able to quote zapper z during class, i think his math teacher will be most impressed.
 Well yet again i get to an intresting thread late! So im going to give my 2cents worth any way even if the question has been answered I think the question that TheSpeed=DUCK asked is answered by Bohrs Postulate. Neils Bohr in 1913 postulated that the angular momentum of an orbiting electron was equactly ballanced my the electrical attraction between the positvely charged nucleus and the negative charge on an electron! Now remember that the copenhagen interpritation of Quantum mechanics hadnt been suggested at this time so Bohr only had Classical mechanics and the feild equations of Maxwell to work with. Oh and his postulate only really works for a Hydrogen atom (when you start adding more than one electron the interactions become more complexe as there is replultion between the electrons as well as the attractive force of the nulceus! so her goes : You first need to understand the nature of the attractive force between charged particles this is refered to as the coloumb force [im not going to derive it for you now (unless you really want me to! )] but it basiclly states that the closer two charge particles get the greater the magnitude of the force! Next, gravity doesnt play a part in why the electron stays bound, gravity is a very pathetic force!, yes it its responcible of such weird things like black holes, that swallow entire star systems, but if you try you can create of force greater that the gravitational attraction of the WHOLE EARTH, try it, see how hight you can jump! by the fact that you can prooves just how weak the force is! Anyway i digresss, the angular momentum of an orbiting electron, should if there were no other forces present throw the electron out of its orbit, but it doesn't, so the attractive electrical force and the angular momentum are some how balance, basiclly there is a relativly short sequence of equations that prooves the electrons can only exist at certain distances from the nulceus.
 Zz I am an undergraduate and would want you to correct my misconcept(s). According to HUP $\Delta x.\Delta p \geqq \frac{h}{4 \pi}$. Pluging in values where $\Delta x$ will be the size of the nucleus, we get $\Delta v$ greater than c ! We should not have velocities above c while here even the uncertainity in velocity is greater than c which indicates that our $\Delta x$ is incorrect ==> e- can't be confined to the nucleus. As the neutrons and protons differ in mass by about 10e3 the $\Delta v$ for n/p doesnt come above c ! So they may exist inside the nucleus.