Calculating Water Density at 10.92 km Depth

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Homework Help Overview

The discussion revolves around calculating the density of water at a depth of 10.92 km in the ocean, considering the effects of pressure and compressibility. Participants are analyzing the relationship between pressure, density, and the bulk modulus in the context of fluid mechanics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the definitions and relationships between bulk modulus, compressibility, and density. There are attempts to derive equations relating these variables, with some questioning the original poster's formulation and the values used for density and bulk modulus.

Discussion Status

The discussion is active, with participants providing insights and alternative formulations. There is recognition of potential discrepancies in the values used for density and bulk modulus, and some participants are working through unit consistency. No explicit consensus has been reached regarding the correct approach or values.

Contextual Notes

There is mention of different conventions for denoting bulk modulus and compressibility, which may contribute to confusion. Participants are also considering the implications of using different reference values for water density at the surface.

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At the bottom of the ocean at 10.92 km the pressure is 1.16*10^8 pa.
If the pressure is calculated ignoring the change of density the pressure is 1.10*10^8 pa
I have to calculate the water density at the bottom using the compressibility and the actual pressure.

Since k= - Delta V/Vo*DeltaP
DeltaP*k= - DeltaV/Vo and V=m/rho
DeltaP*k=-(rho1-rho2)/rho2 where rho1 and rho2 are the water density at the surface and at the bottom respectively.
I end up with:
rho2=-rho1/(DeltaP*k -1)

From this I get rho2 as 1033 pa but I should get 1080 pa

Could someone please give me a hint to what I am doing wrong?


Thanks.
 
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I don't recognize your form of the definition of the bulk modulus. It should be in the form of:

[tex]k = -V \frac{\Delta P}{\Delta V}[/tex]

I am still working through the units. You should end up with kg/m^3 for density, not Pa. Pascals are units of pressure.
 
OK. I finally went thru it. First, it will depend on what values you are using for the density of water at the surface and for the bulk modulus.

After substituting [tex]\rho = \frac{m}{V}[/tex] in the above definition and some algebra, I end up with:

[tex]k = - \frac{\Delta P}{\frac{\rho_1}{\rho_2} - 1}[/tex]

Like I said, it depends on what you use for k and [tex]\rho[/tex] at the surface. I used k = 2.2x10^9 and [tex]\rho_1[/tex] = 1000 kg/m^3 and ended up with a result of [tex]\rho_2[/tex] = 1055.6 kg/m^3 which is pretty close to what you say numerically you should get.
 
Last edited:
I don't understand.
According to my textbook the bulk modulus is -DeltaP*V/DeltaV

The compressibility, k is the reciprocal of the bulk modulus and so is
k=-DeltaV/V*DeltaP
 
Ahh. I see. I'm used to seeing "k" for bulk modulus and "c" for compressibility. It doesn't really matter though. It should all work out in the end. If you solve my equation for bulk modulus for [tex]\rho_2[/tex] and invert it, you will get the same result that you have in your original post.

Also, it might help if you were to present the equation as: k = -DeltaV/(V*DeltaP). I am admittedly horrible when having to do orders of operation, so I like to see parentheses.

What values did you use for the density at sea level and for compressibility? Did you see my comment about the units you ended up with?
 

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