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Brain Teaser #63

What is the sum of all the numbers formed by taking each of the digits 2,3,5,6 and 8 once?
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 haha, maybe later.
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Brain Teaser #63

 Originally posted by jamesrc 6399936
How'd ya get that answer? [:)]
 Hmm...combinatorics. 2 3 5 6 8 There are: (5)*(5-1)*(5-2)*(5-3)*(5-4) or 5*4*3*2*1 = 120 permutations for the above set of numbers. One set of numbers add up to: 2+3+5+6+8 = 24. So, the sum of all numbers formed from 120 permutations is: 120*24 = 2880.
 Recognitions: Gold Member Science Advisor If I answered the right question, for all of the 5-digit numbers you can make, each digit appears 24 times in each column, so you can write: 24*(22222+33333+55555+66666+88888)=6399936 Edit: Oh, I thought it was the sum of the numbers made by the combinations, not the sum of their digits.

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 Originally posted by jamesrc If I answered the right question, for all of the 5-digit numbers you can make, each digit appears 24 times in each column, so you can write: 24*(22222+33333+55555+66666+88888)=6399936 Edit: Oh, I thought it was the sum of the numbers made by the combinations, not the sum of their digits.
James gets the point!

Here is an alternative way:
4!*(2+3+5+6+8)*(11111) = 6,399,936

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