Find Angle Between Avec and Bvec: Rads Formula Explained

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Homework Help Overview

The discussion revolves around finding the angle between two vectors, A(vec) and B(vec), using the dot product formula. The original poster presents the vectors and attempts to apply the formula involving the cosine of the angle.

Discussion Character

  • Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use the dot product to find the angle but questions the validity of their calculations, particularly regarding the magnitudes of the vectors.

Discussion Status

Participants are actively clarifying the calculations related to the magnitudes of the vectors. Some guidance has been provided regarding the correct values for the magnitudes, indicating a productive direction in the discussion.

Contextual Notes

There appears to be confusion regarding the calculations of the magnitudes of the vectors, which is central to applying the dot product formula correctly. The original poster acknowledges a mistake in their multiplication.

philo51
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A(vec)=(2,1,-4) B(vec)=(-3,0,1) C(vec)=(-1,-1,2)

whats the angle between Avec and Bvec in rads.

i know the formula

A(vec)*B(vec)= abs(A)*abs(B)*cos(theta)

A(vec)*B(vec)=-10

so why won't cos^-1(-10/(21)(10)) work?
 
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absA = [itex]\sqrt{21}[/itex], not 21
 
that still isn't right?
 
What still isn't right?

You were told that the length of vector A is [tex]\sqrt{21}[/tex], not 21.

Did it then occur to you that the length of vector B should be [tex]\sqrt{10}[/tex], not 10?

Try [tex]\theta= cos^{-1} \frac{-10}{\sqrt{210}}[/tex].
 
no i realized that i just multiplied weird.. sorry thanks!
 

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